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3 years ago

10

Some help me with this

2 answers:

Maslowich3 years ago

8 0

17.50 + (1.75 x 18) + (.65 x 12)
17.50 + 31.50 + 7.80
56.80

$56.80 is your answer.

VikaD [51]3 years ago

8 0

I believe the answer is $62.80

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In a recent student body election, Adam received 40 more than 40% of the votes. Brigitte received 40 less

Airida [17]

The total vote cast was 700.

The winner was Adam (received 320 votes)

Why?

To solve the problem, we need to make equations to express the number of votes received for each of the candidates.

Solving we have:

Let be "v" the total vote cast,

For Adam,

$A=40+0.4*v$

For Brigitte,

$B=0.5(40+0.4v)-40$

$B=20+0.2v-40$

$B=0.2v-20$

For Carl,

$C=20+0.5*B$

$C=20+0.5*(0.2v-20)$

$C=10+0.1v$

For Diane,

$D=180votes$

Now, the total vote cast will be:

$v=A+B+C+D\\\\v=(40+0.4v)+(0.2v-20)+(10+0.1v)+180\\\\v=(40-20+10+180)+(0.4v+0.2v+0.1v)$

$v=210+0.7v\\\\v-0.7v=210\\\\v=\frac{210}{0.3}=700$

Now, substituting "v" in each equation to calculate the number of votes for each candidate, we have:

$Adam=40+0.4*700=320votes\\Brigitte=0.2*700-20=120votes\\Carl=10+0.1*700=80votes\\Diane=180votes$

Hence, we have that the total vote cast was 700, and the winner was Adam (received 320 votes)

Have a nice day!

7 0

3 years ago

X2-8x+10=0 solve for x

Oksi-84 [34.3K]

Answer: x = 5/3

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

If an equation has an identity how many equations does it have

melamori03 [73]

Answer:

Is there anyway you can explain it more?

8 0

3 years ago

Read 2 more answers

Please whats the answer to this question

Shkiper50 [21]

I believe it’s 800 cm^3

4 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP -- WITH THE WORKK<br><br>50 points

MAXImum [283]

Part-A:-

<h3>(f×g)=</h3>

$\\ \sf\longmapsto x^2+3x-70(4x-12)$

$\\ \sf\longmapsto 4x^2+12x-280-12x^2+36x+840$

$\\ \sf\longmapsto -8x^2+48x+560$

Now

$\\ \sf\longmapsto (f.g)(3)$

$\\ \sf\longmapsto -8(3)^2+48(3)+560$

$\\ \sf\longmapsto -72+144+560$

$\\ \sf\longmapsto 72+560$

$\\ \sf\longmapsto 632$

Part-B:-

$\\ \sf\longmapsto f(3)$

$\\ \sf\longmapsto (3)^2+3(3)-70$

$\\ \sf\longmapsto 9+9-70$

$\\ \sf\longmapsto 18-70$

$\\ \sf\longmapsto -52$

Now

$\\ \sf\longmapsto g(f(3))$

$\\ \sf\longmapsto g(-52)$

$\\ \sf\longmapsto 4(-52-3)$

$\\ \sf\longmapsto 4(-55)$

$\\ \sf\longmapsto -220$

Part:-C

$\\ \sf\longmapsto g(-2)$

$\\ \sf\longmapsto 4(-2-3)$

$\\ \sf\longmapsto 4(-5)$

$\\ \sf\longmapsto -20$

Now

$\\ \sf\longmapsto f(g(-2))$

$\\ \sf\longmapsto f(-20)$

$\\ \sf\longmapsto (-20)^2+3(-20)-70$

$\\ \sf\longmapsto 400-60-70$

$\\ \sf\longmapsto 400-130$

$\\ \sf\longmapsto 270$

Part-D:-

g×f=f×g

$\\ \sf\longmapsto (g.f)(-2)$

$\\ \sf\longmapsto -8(-2)^2+48(-2)+560$

$\\ \sf\longmapsto 32-96+560$

$\\ \sf\longmapsto -64+560$

$\\ \sf\longmapsto 496$

6 0

3 years ago