Answer:
Opt. D.
Step-by-step explanation:
To solve this problem we need to focus our attention in the abs(x-1) function,
If x>1, then abs|x-1|= x-1, if x<1 then abs|x-1|= 1-x. And in the two intervals, the function opens upwards.
But our function has -3 multiplying abs|x-1|, This means that our function opens downward.
The vertex point can be found when x=1, since abs(x-1)=0. this gives f(1)=12
2.
The domain of this function is 3≤x≤5 in interval notation that is [3,5]
The range is -3≤y≤3. In interval notation that is [-3,3]
4.
The domain of this function is -5≤x≤-1 in interval notation that is [-5,-1]
The range is 1≤y≤5. In interval notation that is [1,5]
:)
I am going to add and subtract and if u see one of the answers on your assignment yw.
60+12=72
60-12=48
Hope this helps
The answer to your math problem is 4x=x^2-12