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loris [4]
4 years ago
15

Write an equation that will help them determine how much a tip they should leave

Mathematics
1 answer:
olga_2 [115]4 years ago
6 0

Answer:

You take how much it cost by 20 percent and that's how much their tip is

Step-by-step explanation:

7.12

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How do you write fourteen and seven-tenths squared in all three froms
Oduvanchick [21]
10 + 4 + 0.7 + /10
fourteen and seven-tenths
14 7/10
6 0
3 years ago
Consider the equation 5-3(2x - 7) = 12-5(x - 2). Is x = 2 a solution to this equation? Is x = 4 a solution to this equation? Exp
mario62 [17]

Answer:

x=4

Step-by-step explanation:

5-3(2x-7)=5-6x+21=-6x+26

--------------------------------------

12-5(x-2)=12-5x+10=-5x+22

--------------------------------------

-6x+26=-5x+22

-6x-(-5x)=22-26

-6x+5x=-4

-x=-4

x=4

8 0
3 years ago
Find the percent of change from 32 feet to 79 feet. Round to the nearest tenth, if necessary. Then state whether the percent of
mixer [17]

Answer:

71 1/4%

Step-by-step explanation:

I think the change is percentage increase. the method of finding percentage iincrease is increase over percentage increase x 100%

8 0
3 years ago
North side dormitory just purchased a new DVD player on sale for $416. The sale price was 80% of the original price. What was th
Diano4ka-milaya [45]
100 - 80% = 20 %
20% = $416
416 x 5 = $2080 = 100%
7 0
3 years ago
A box with a height (x+5) has a square base with side x. A second box with height (x+2) has a square base with side (x+5). If th
sergeinik [125]

Answer :

x = -1.43

Explanation :

As given ,

The first box has a height (x+5) has a square base with side x

So, the Length and Breadth of the box are x and x respectively.

Now,

The volume of first box = Length×Breadth×Height

                                       = (x).(x).(x+5)

                                       = x²(x+5)

⇒The volume of first box = x²(x+5)

Now,

Given that , the second box with height (x+2) has a square base with side (x+5).

So, the Length and Breadth of the box are (x+5) and (x+5) respectively.

Now,

The volume of second box = Length×Breadth×Height

                                             =  (x+5). (x+5).(x+2)

                                              = (x+5)²(x+2)

⇒The volume of second box =  (x+5)²(x+2)

Now,

Given that,  the two boxes have the same volume

⇒x²(x+5) =  (x+5)²(x+2)

⇒x² =  (x+5)(x+2)

⇒x² =  x² + 2x + 5x + 10

⇒x² - x² =  7x + 10

⇒0 =  7x + 10

⇒ 7x = -10

⇒ x = -\frac{10}{7} = -1.43

⇒ x = -1.43

As volume of first box = x²(x+5) = (-1.43)²(-1.43+5) = 7.30 ≈ 7

As volume of second box =  (x+5)²(x+2) = (-1.43+5)²(-1.43+2) = 7.26 ≈ 7

At x = -1.43, Volume of both the boxes are same.

4 0
3 years ago
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