Question

n a trip, a motorist drove 150 miles in the morning and 50 miles in the afternoon. His average rate in the morning was twice his average rate in the afternoon. He spent 5 hours driving. Find his average rate on each part of the trip.

Answer 1

Answer:

Step-by-step explanation:

A motorist drove 150 miles in the morning and 50 miles in the afternoon

His average rate in the morning was twice his average rate in the afternoon

He spent 5 hours driving

As=t*d

Cross multiply!!!

This is the equation

(750 - 150x = 100x =250x = 750 = x=3)

AS (Average speed  is 50 mph

AS 25 mph

Hope it helps!

Answer 2

Answer:

His average rate in the morning was $50\ \frac{mi}{h}$

His average rate in the afternoon was $25\ \frac{mi}{h}$  

Step-by-step explanation:

We need to remember the following formula:

$V=\frac{d}{t}$

Where "V" is the speed, "d" is the distance and "t" is the time.

Solving for "t":

$t=\frac{d}{V}$

Let be $x$ the average rate in the afternoon and $2x$ the average rate in the morning.

Since he spent 5 hours driving, we can write the following equations:

$5=\frac{150}{2x}+\frac{50}{x}$

Solving for "x", we get:

$5=\frac{150}{2x}+\frac{50}{x}\\\\5=\frac{75+50}{x}\\\\5x=125\\\\x=\frac{125}{5}\\\\x=25$

Therefore, his average rate in the afternoon was:

$x=25\ \frac{mi}{h}$

And his average rate in the morning was:

$2x=2(25)=50\ \frac{mi}{h}$