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sashaice [31]
3 years ago
15

Larry paid 11.20 for four gallons of gas. How much was each gallon of gas

Mathematics
2 answers:
GarryVolchara [31]3 years ago
8 0
All u do is divide 11.20 by 4 which is 2.8 which is 2.8 so each gallon costs $2.8.
kobusy [5.1K]3 years ago
7 0
11.20 : 4 = 2.8
Because when you want to calculate how much money you pay for the number of gallons of gas, you have to take a price of something multiply the number of gallons. Similarly, when you want to find the price of a gallon of gas, you have to take the total cost divided by number of gallons of gas you buy.
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205 dollars today I think
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4 years ago
Which function has a greater y value if x=2<br> O<br> Blue<br> Red
LenaWriter [7]

Answer:

Guessing the answer should be the blue one because it is going up the graph steeper.

Step-by-step explanation:

4 0
3 years ago
Write a point slope equation for -5/7 using the coordinates (6,2)
sleet_krkn [62]

Answer:

(13, -3)

Step-by-step explanation:

slope = -5/7

(6,2)  

m = ( y2 - y1) / ( x2 - x1 )

-5/7 = ( y2 - 2) / ( x2 - 6 )

   

    -5 = y2 -2

        +2        +2

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      7 = x2 - 6

    +6         +6

      13 = x2


Check answer again by log them in:

m = ( y2 - y1 ) / ( x2 - x1 )

m = ( -3 - 2 ) / ( 13 - 6 )

m = -5 / 7


I hope this helps!

7 0
3 years ago
Principle = 30,000<br>Time = 4 years<br>Rate = 30<br>Then find the simple interest ?​
Nutka1998 [239]

Answer:

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}

  • {\dashrightarrow \sf{Principle = Rs.30000}}
  • {\dashrightarrow \sf {Time = 4 \: years}}
  • \dashrightarrow \sf{Rate = 30\%}
  • \begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}

  • \dashrightarrow{\sf{Simple \: Interest }}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}

\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}

Where

  • \dashrightarrow{\sf{S.I = Simple \:  Interest }}
  • {\dashrightarrow{\sf{P = Principle }}}
  • {\dashrightarrow{\sf{ R = Rate }}}
  • {\dashrightarrow{\sf{T = Time}}}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{P \times R \times T}{100}}}}}}

Substituting the values

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 120}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{3600000}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\cancel{\dfrac{3600000}{100}}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{Rs.36000}}}}}

{\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}

  • Henceforth,The Simple Interest is Rs.36000..

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

8 0
3 years ago
Read 2 more answers
What is 15% of 135, show your work
SIZIF [17.4K]

Answer:

20.25

Step-by-step explanation:

Percentage solution with steps:

Step 1: Our output value is 135.

Step 2: We represent the unknown value with $x$

.

Step 3: From step 1 above,$135=100\%$

.

Step 4: Similarly, $x=15.\%$

.

Step 5: This results in a pair of simple equations:

$135=100\%(1)$.

$x=15.\%(2)$

.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{135}{x}=\frac{100\%}{15.\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{135}=\frac{15.}{100}$

$\Rightarrow x=20.25$Therefore, $15.\%$ of $135$ is

sorry if it took to long have a great day and brainliest is appreciated!!!!!

5 0
3 years ago
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