NO.,the given measures can not be the lengths of the sides of a triangle
Step-by-step explanation
The sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
so, Find the range for the measure of the third side of a triangle given the measures of two sides.
here given measures are 2,2,6
2+2 = 4 which is less than the third side 6
= 4 < 6
This not at all a triangle.
Hence, the given measures can not be the lengths of the sides of a triangle
Answer:
See Explanation
Step-by-step explanation:
Your question is incomplete, as the equations or graph or table(s) were not given.
However, I'll give a general way of solving this.
Take for instance, the equations are:
To do this, we start by equating both equations.
i.e.
Collect Like Terms
Take LCM
Cross Multiply
Make x the subject
Substitute 3/4 for x in
Hence:
Answer:
y ≥ 8
Explanation:
Note that if f(x) is transformed into f(x + a) - b
The original functions is shifted a units to the left and b units downward.
Horizontal shifting will not affect the range of the function, only vertical shifting will change its range.
From the given, g(x) is the transformation of f(x) with
f(x) is shifted 2 units to the left and 3 units downward, we will disregard the horizontal shifting.
Since f(x) has a range of y ≥ 11, and g(x) is 3 units downward, the range will also move 3 units downward.
y ≥ 11 - 3
The answer is y ≥ 8
Answer:
17.7
Step-by-step explanation:
angle B = 180 - 81 - 65 = 34 degrees
as the sum of all angles in any triangle is always 180 degrees.
a/sin(A) = b/sin(B) = c/sin(C)
the sides are always on the opposite side of the angle.
so,
10/sin(34) = AB/sin(81)
AB = 10×sin(81) / sin(34) = 17.7
Answer:
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