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Tamiku [17]
3 years ago
9

Help me please!!!!!!!

Mathematics
1 answer:
Likurg_2 [28]3 years ago
6 0

9514 1404 393

Answer:

  1

Step-by-step explanation:

First, look up g(1), then look up the value of f(x) corresponding to x=g(1).

  f(g(1)) = f(-1) = 1

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17x2 - 5x + 10x - 8x2
USPshnik [31]

Answer:

9x2+5x

Step-by-step explanation:

combine like terms

4 0
3 years ago
For the equation x = 5 t − 3 , what does x equal when t = 12?
kodGreya [7K]

Answer: <em>x=57</em>

Step-by-step explanation:

<em>Let's take our equation</em>

<em />x=5(t)-3\\x=5(12)-3\\x=60-3\\x=57<em />

7 0
3 years ago
Math Exit Slip: Value-Mart is having a back -to - school sale on pencils. A pack of of 20 sells for $7.97, whereas a 12-pack cos
Whitepunk [10]

Answer: The pack of 20.

Step-by-step explanation:

It is because a pack of 20 sells for 2.50 for each pencil, and the pack of 12 sells for 2.51 per pencil, so that means the pack of 20 is cheaper.

4 0
3 years ago
The sum of person x and person y is 2640. if person x's income is 20% more than person y, find person x's income.
Masja [62]

Answer:

I do not understand she question do you mean the sum of their income is 2640

if so, then the answer is 440 to be x income

Step-by-step explanation:

x income = 20% or 1/5 of y income

y income = 5 of x income

we know that the sum of their income = 2640

which means that

x + y = 2640 =

1/5y + y = 2640

6y/5 = 2640

cross multiply to give us

6y = 5(2640)

6y = 13200

divide through by 6 to give us,

6y/6 = 13200/6

y = 2200

since we know that x income is 20% y income,

therefore, x income =

20/100 * 2200

= 440

therefore,

x income = 440

y income = 2200

5 0
3 years ago
Read 2 more answers
Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without b
Korolek [52]
Hello,

Very nice as problem.

2 solutions:
1 quater,8 dimes, 2 pennies
and
3 quaters,3 dimes, 2 pennies

since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0



4 0
3 years ago
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