Question

16. The difference of two numbers is 3 and the

Answer 1

Make a system of equations.

$x-y=3$

$x^2-y^2=69$

$x=y+3$

$(y^2+6y+9)-y^2=69$

$6y+9=69$

$6y=60$

$y=10$

$x=10+3$

$x=13$

$x=13,y=10$

Hope this helps.

頑張って!