Answer:

Step-by-step explanation:
To solve this operation we need to find the common multiple of both denominators and solve for a.

Thus, the solution is 7(a -1) / (a+2)(a-5)
Answer:
45/r
Step-by-step explanation:
You're just doing 45 divided by r.
My answer is A. Hands down A.
X = -2 and -5
You can set both equal to 0 to find the answers.