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Komok [63]
3 years ago
10

Answer please mmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Mathematics
1 answer:
Tju [1.3M]3 years ago
8 0

Answer:

0

Step-by-step explanation:

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                     1 4, 5 0 9
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A deep sea diver is 4.5m below the water level At what depth he is now ? At what height is he now
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Answer:

Step-by-step explanation:

Below the sea level should be mentioned by negative value

So, It is  =  - 4.5

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Find the Least Common Denominator of the fractions: 6/7 and 2/3
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The least common denominator is 21

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A) 197 degree<br> B) 261 degree<br> C) 211 degree<br> D) 236 degree
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Answer:

Option D.) 236 degrees

Step-by-step explanation:

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<em>2 * ∠GFE = Arc GE (?)</em>

2 * 118 = Arc GE (?)

<u>236 = Arc GE (?)</u>

Hope this helps!

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3 years ago
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A manager of a grocery store wants to determine if consumers are spending more than the national average. The national average i
strojnjashka [21]

The valid conclusions for the manager based on the considered test is given by: Option

<h3>When do we perform one sample z-test?</h3>

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

  • Population mean = \mu = $150
  • Population standard deviation = \sigma = $30.20
  • Sample mean = \overline{x} = $160
  • Sample size = n = 40 > 30
  • Level of significance = \alpha = 2.5% = 0.025
  • We want to determine if the average customer spends more in his store than the national average.

Forming hypotheses:

  • Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get: H_0: \mu_0 \leq \mu = 150
  • Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically H_1: \mu_0 > \mu = 150

where \mu_0 is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

Learn more about one-sample z-test here:

brainly.com/question/21477856

3 0
1 year ago
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