If you use this equation then you say that the ground is h=0 and solve as a quadratic.
The quadratic formula is (-b±<span>√(b^2-4ac))/2a when an equation is in the form ax^2 + bx + c
So the equation you have been given would be -16t^2-15t-151 = 0
This equation has no real roots which leads me to believe it is incorrect.
This is probably where your difficulty is coming from, it's a mistake.
The equation is formed from S=ut+(1/2)at^2+(So) where (So) is the initial height and S is the height that you want to find.
In this case you want S = 0.
If the initial height is +151 and the initial velocity and acceleration are downwards (negative) and the initial velocity (u) is -15 and the initial acceleration is -32 then you get the equation S=-15t-16t^2+151
Solving this using the quadratic formula gives you t = 2.64 or t = -3.58
Obviously -3.58s can't be the answer so you're left with 2.64 seconds.
Hope this makes sense.
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Answer:
AB = square root of 403
Step-by-step explanation:
use the pythagorean theorem to solve for AB.
a^2 + b^2 = c^2
9^2 + b^2 = 22^2
81 + b^2 = 484
b^2 = 484 - 81
b^2 = 403
b = 20.07
For this case we have that Lauren's initial amount of money was $ 50, if he spends $10 and $12 on admission and strawberry pie respectively we have:
$50 - ($10 + $12) = $50- $22 = $28
That is, she has $ 28 left
n: Let the variable that represents the amount of games Lauren can play.
Then, it must be fulfilled that:
Thus, Lauren can play 37 times the game (at most)
ANswer:
Thus, Lauren can play 37 times the game (at most)
Answer:
lol
Step-by-step explanation:
Answer: go to google and use a calculater
Step-by-step explanation:
