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-Dominant- [34]
3 years ago
14

If triangle ABC with vertices A(-2, -5), B(-3, 2), and C (1, -2) a right triangle?

Mathematics
1 answer:
V125BC [204]3 years ago
7 0
Hello :
<span>A(-2, -5), B(-3, 2), and C (1, -2) 
calculate : AB² , AC² ,BC²
</span> AB² = ( -3  +2   )² +  ( 2  +5  )² =50
AC² = ( 1  +2  )² +  ( -2  +5   )²  =18
BC² = (  1 +3  )² +  ( -2  - 2  )²  = 32
by petagor rule  :  AB² =  AC² + BC²....(<span>ABC is a </span>right triangle in : C )
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HELP PLEASEEE!!
Luden [163]

\left[\begin{array}{ccc}2&6&3\\-5&1&4\end{array}\right]

R1 ÷ 2  = \left[\begin{array}{ccc}1&3&1.5\\-5&1&4\end{array}\right]

R2 ÷ -5 = \left[\begin{array}{ccc}1&3&1.5\\1&-0.2&-0.8\end{array}\right]

R2: R1 - R2  = \left[\begin{array}{ccc}1&3&1.5\\0&3.2&2.3\end{array}\right]

R2 ÷ 3.2 =  \left[\begin{array}{ccc}1&3&1.5\\0&1&0.71875\end{array}\right]

R1: R1 - 3R2 = \left[\begin{array}{ccc}1&0&0.65625\\0&1&0.71875\end{array}\right]

Answer: x = 0.65625, y = 0.71875

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3 years ago
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Step-by-step explanation:

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IRISSAK [1]

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Step-by-step explanation:

4 0
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