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laila [671]
3 years ago
8

Use the number line to solve 235 +123

Mathematics
1 answer:
Shalnov [3]3 years ago
4 0
Its easy :) Use the number line on the page to find 235 and 123 and add it up.
235 + 123 = 358
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Trent made 11 free throws out of 15 attempts during the basketball game.What was his free-throw average expressed as a decimal?
nlexa [21]
\frac{11}{15}  =\boxed{\bf{0.733333333...}}
5 0
3 years ago
What is the approximate volume of a basketball with the circumference of 42ft ?
Semmy [17]
We know that

[volume of a sphere]=(4/3)*pi*r³

length of a circumference=42 ft
[length of a circumference]=2*pi*r-------> r=[length of a circumference]/(2*pi)
r=[42]/(2*pi)---------> r=6.6845 ft

[volume of a sphere]=(4/3)*pi*6.6845³-----------> 1251.11 ft³

the answer is 1251.11 ft³
4 0
3 years ago
△DEF is shown below.<br><br>Triangle DEF<br><br>What is m∠DEF?​
S_A_V [24]

Answer:

m∠DEF = 50

Step-by-step explanation:

∠DEG = ∠GEF

3y + 4 = 5y - 10

subtract 4 from both sides

3y = 5y - 14

subtract 5y from both sides

-2y = -14

divide by -2

y = 7

Add 7 into the equations:

3y + 4 + 5y - 10

3(7) + 4 + 5(7) - 10

21 + 4 + 35 - 10

25 + 25

50

4 0
3 years ago
Find the area of the figure. please help my teacher is waiting.......
katrin [286]

Answer:

The area of the shape is 89m²

Step-by-step explanation:

You need to subtract the area of the empty triangle from the area of the rectangle.

The rectangle's area is 13m × 8m = 104m²

The triangle's area is (6m × (13 - 8)m) / 2 = (6 × 5) / 2 m² = 15m²

Subtract the triangle's area from the rectangle:

104m² - 15m²

= 89m²

7 0
3 years ago
Determine the sample size needed to construct a 99​% confidence interval to estimate the average GPA for the student population
Volgvan

Answer: n = 14

Step-by-step explanation: margin of error = critical value × σ/√n

Where σ = population standard deviation = 1

n = sample size = ?

We are to construct a 99% confidence interval, hence the level of significance is 1%.

The critical value for 2 tailed test at 1% level of significance is gotten from a standard normal distribution table which is 2.58

Margin of error = 0.7

0.7 = 2.58×1/√n

0.7 = 2.58/√n

By cross multipying

0.7×√n = 2.58

By squaring both sides

0.7^2 × n = 2.58^2

0.49 × n = 6.6564

n = 6.6564/0.49

n = 14

3 0
3 years ago
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