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sertanlavr [38]

3 years ago

11

A farmer wants to plant peas and carrots on no more than 200 acres of his farm. If x represents the number of acres of peas and

y represents the number of acres of carrots for solution (x, y), then which is a viable solution?
A.(−50, 160)
B.(80, 160)
C.(75, −200)
D.(60, 135)

2 answers:

n200080 [17]3 years ago

8 0

Answer:

it's D

Step-by-step explanation:

AfilCa [17]3 years ago

5 0

Answer:

Option D.(60, 135)

Step-by-step explanation:

Let

x -----> the number of acres of peas

y ----> the number of acres of carrots

we know that

The inequality that represent the problem is equal to

$x+y\leq 200$

so

<em>Verify each case</em>

case A) (-50,160)

substitute the value of x and the value of y in the inequality and then compare the result

$-50+160\leq 200$

$110\leq 200$ ----> is true

The point is a solution for the inequality, but is not a viable solution because the number of acres can not be a negative number

case B) (80,160)

substitute the value of x and the value of y in the inequality and then compare the result

$80+160\leq 200$

$240\leq 200$ ----> is not true

therefore

The point is not a solution

case C) (75,-200)

substitute the value of x and the value of y in the inequality and then compare the result

$75-200\leq 200$

$-125\leq 200$ ----> is true

The point is a solution for the inequality, but is not a viable solution because the number of acres can not be a negative number

case D) (60,135)

substitute the value of x and the value of y in the inequality and then compare the result

$60+135\leq 200$

$195\leq 200$ ----> is true

therefore

The point is a viable solution

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blondinia [14]

The trick is to exploit the difference of squares formula,

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$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Question 11 :

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