Answer:
m∠BCE = 28° and m∠ECD = 134°
Step-by-step explanation:
* Lets explain how to solve the problem
- The figure has three angles: ∠BCE , ∠ECD , and ∠BCD
- m∠ECD is six less than five times m∠BCE
- That means when we multiply measure of angle BCE by five and
then subtract six from this product the answer will be the measure
of angle ECD
∴ m∠ECD = 5 m∠BCE - 6 ⇒ (1)
∵ m∠BCD = m∠BCE + m∠ECD
∵ m∠BCD = 162°
∴ m∠BCE + m∠ECD = 162 ⇒ (2)
- Substitute equation (1) in equation (2) to replace angle ECD by
angle BCE
∴ m∠BCE + (5 m∠BCE - 6) = 162
- Add the like terms
∴ 6 m∠BCE - 6 = 162
- Add 6 to both sides
∴ 6 m∠BCE = 168
- Divide both sides by 6
∴ m∠BCE = 28°
- Substitute the measure of angle BCE in equation (1) to find the
measure of angle ECD
∵ m∠ECD = 5 m∠BCE - 6
∵ m∠BCE = 28°
∴ m∠ECD = 5(28) - 6 = 140 - 6 = 134°
* m∠BCE = 28° and m∠ECD = 134°
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2. C
Slope = 40/8 = 5
Slope of graph c = 5/1 = 5
3. D
Slope = 9/3 = 3
Slope of graph d = 81/27 = 3
Answer:
2np + p²
Step-by-step explanation:
The general formula for the area of a square is A = s², where s = the length of one side of the square. In the case of the smaller square the area would be: n x n = n². Since the side of the larger square is 'p' inches longer, the length of one side is 'n + p'. To find the area of the larger square, we have to take the length x length or (n +p)².
Using FOIL (forward, outside, inside, last):
(n + p)(n+p) = n² + 2np + p²
Since the area of the first triangle is n², we can subtract this amount from the area of the larger square to find out how many square inches greater the larger square area is.
n² + 2np + p² - n² = 2np + p²
Answer:
Volume of water and air is 3,000 mm³
Step-by-step explanation:
Given:
Length of base = 15 mm
Width of base = 20 mm
Height of figure = 30 mm
Find:
Volume of water and air is inside each of the plastic ice cubes.
Computation:
Height of each rectangular pyramid = Height of figure / 2
Height of each rectangular pyramid = 30 / 2
Height of each rectangular pyramid = 15 mm
Volume of each rectangular pyramid = lbh / 3
Volume of each rectangular pyramid = [15 × 20 × 15] / 3
Volume of each rectangular pyramid = [4,500] / 3
Volume of each rectangular pyramid = 1,500 mm³
Volume of water and air is inside each of the plastic ice cubes = 2 × Volume of each rectangular pyramid
Volume of water and air is inside each of the plastic ice cubes = 2 × 1,500
Volume of water and air is inside each of the plastic ice cubes = 3,000 mm³
