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3 years ago

This equation is an example of:

Mathematics

2 answers:

mariarad [96]3 years ago

4 0

Answer:

B. FOIL

Step-by-step explanation:

FOIL stands for Firsts, Outsides, Insides, and Lasts

This is a mnemonic to help you to remember how to multiply two binomials

From the image, we can see that the on the right side of the equals,

$(x)(-5x^2)$ is the product of the firsts of the binomials

$(x)(x)$ is the product of the outsides of the binomials

$(-2)(-5x^2)$ is the product of the insides of the binomials

$(-2)(x)$ is the product of the lasts of the binomials.

hoa [83]3 years ago

4 0

Answer:

B. FOIL

Step-by-step explanation:

"FOIL" is an acronym for First, Outer, Inner, Last. It refers to the relative positions of the terms in the multiplication of binomials.

The given equation shows the result of such a multiplication. It is an example of the application of FOIL.

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75,100,125, what comes next

Alchen [17]

Answer:

150

Step-by-step explanation:

add 25 and you get the next number

8 0

3 years ago

What is the prime factorization of 630

Kisachek [45]

630|2
315|3
105|3
35|5
7|7
1

$630=2\cdot3^2\cdot5\cdot7$

3 0

3 years ago

What is the value of 9 in 37.0691

mixer [17]

The answer would be thousands

3 0

3 years ago

A bus leaves a station traveling north at 70 kilometers per hour. Half an hour later a

Semenov [28]

Answer:

280 km

Step-by-step explanation:

Given that a bus, say $b_1$ , leaves a station traveling north at speed of 70km/hour.

Half an hour later the second bus, say $b_2$ , leaves a station traveling north at speed of 70km/hour.

As, distance = speed x time,

so, the distance traveled by bus $b_1$ in 0.5 hours = 70 x 0.5 = 35 km.

Note that, both the buses are traveling in the same direction and when the second bus leaves the station, the first bus already covered a distance of 35 km.

Let the second bus took $t$ hours to meet the first bus and both the buses meet at a distance of $d$ km from the station.

The distance traveled by the first bus from the station, $d = 35 + 70t$ km

$\Rightarroe t= \frac {d-35}{70}\cdots(i)$

and the distance traveled by the second bus, $d = 80t$ km

$\Rightarrow t=\frac {d}{80}\cdots(ii)$

Now, equation the equation (i) and (ii), we have

$\frac {d-35}{70}=\frac {d}{80} \\\\\Rightarrow 8(d-35)=7d \\\\\Rightarrow 8d - 280 = 7d \\\\\Rightarrow 8d-7d=280 \\\\\Rightarrow d = 280 km$

Hence, both the bus will meet at a distance of 280 km from the station.

7 0

3 years ago

Is it true that to finding the LCM you have to divide the product but he GCF? If not give in example why not, and if it’s true,

tiny-mole [99]

To find the LCM, you CAN divide the product of the two numbers by the GCF.

This is not a very well-known fact, but it is useful at times, especially when we are asked to calculate both the LCM and GCF.

For example, the GCF of 18 and 48 is 6, by inspection or by factors.

Therefore the LCM of 18 and 48 is 18*48/6=864/6=144.

It works because by definition the GCF is the products of all common factors between the two given numbers. Dividing the product by the GCF will therefore remove the duplication of the common factors, leaving a number which contains the factors of each of the two numbers, thus a lowest common multiple.

Note that this method is not the only way to find LCM's.

4 0

3 years ago