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marin [14]
3 years ago
11

How do I find the missing pairs ?

Mathematics
2 answers:
Delvig [45]3 years ago
5 0
Hello we know that the triangles are proportional so they have the same ratio
the unknown side is 21 because of this.
18/6=3/1
for each 1 unit in the bottom triangle there are 3 in the top
9×3=21
Alexus [3.1K]3 years ago
4 0
The ▲TSU ~ ▲KLJ
|KS| and |KL| are similar.
|TU| and |KJ| are similar.

1st/2nd = 1st/2nd
18/6= x/9
3/1= x/9

9 is nine times more 1
so the x must be nine times more as well.
3.9=27

Hope it helps!
#MissionExam001

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Plzz help steps if possible if not its ok j=i just need to pass this class
hammer [34]

Answer:

\text{(B) }\cos 40^{\circ}=\frac{x}{60}

Step-by-step explanation:

In any triangle, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse (longest side) of the triangle. (a/h)

The angle marked 40 degrees has an adjacent side of x and the hypotenuse of the triangle is 60.

Therefore, we have the equation:

\boxed{\cos 40^{\circ}=\frac{x}{60}}

6 0
3 years ago
Find the general solution of the given higher-order differential equation. d3u dt3 + d2u dt2 − 2u = 0
STALIN [3.7K]

\dfrac{\mathrm d^3u}{\mathrm dt^3}+\dfrac{\mathrm d^2u}{\mathrm dt^2}-2u=0

This ODE has characteristic equation

r^3+r^2-2=(r^3-r)+(r^2+r-2)=r(r^2-1)+(r+2)(r-1)

=(r(r+1)+(r+2))(r-1)=(r^2+2r+2)(r-1)=0

which has roots at r=1,-1\pm i. Then the characteristic solution to the ODE is

u(t)=C_1e^t+C_2e^{(-1+i)t}+C_3e^{(-1-i)t}

\implies\boxed{u(t)=C_1e^t+C_2e^{-t}\cos t+C_3e^{-t}\sin t}

6 0
3 years ago
At the park there is a pool shaped like a circle. A ring-shaped path goes around the pool. Its inner diameter is 22yd and its ou
jeka94
First, we need to think about what we're actually solving for: the area of the path. To find this, we can find the area of the whole thing, minus the area of the pool.

The diagram would look something like the picture I attached. We know that to find the area of a circle, you do πr^2. The radius is half of the diameter, so halve the diameters:

22/2 = 11 yards
32/2 = 16 yards

Then solve for the area of both circles.
π11^{2}= 121π ≈ <span>380.13 (area of the pool)</span>
π16^{2}= 256π ≈ <span>804.25 (area of the whole thing)
</span>
Next, subtract the area of the pool from the area of the whole thing to find the area of the walkway:
804.25 - 380.13 = 424.12 (area of the walkway)

Finally, divide the area of the walkway by 6 to see how many gallons of paint you'll need:

424.12 ÷ 6 ≈ 70.69

So you'll need 71 gallons of paint!

Hope I helped and let me know if you have any questions :)


6 0
3 years ago
If you know the length of sides b and c of a right triangle, which equation represents the length of side a, according to the Py
Reptile [31]

Answer:

A=SqRt(c^2-b^2)

Step-by-step explanation:

a^2 + b^2 = c^2

rearrange to solve for a^2

a^2= c^2-b^2

take the square root of each side

a= square root (c^2-b^2)

3 0
3 years ago
Ma<br>Find the co-ordinate the image of a <br>point 6,4). Rotate it than<br>270<br>de acee​
telo118 [61]

Answer:

(4, - 6 )

Step-by-step explanation:

Under a counterclockwise rotation about the origin of 270°

a point (x, y ) → (y, - x ) , thus

(6, 4 ) → (4, - 6 )

6 0
3 years ago
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