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3 years ago

How many tenths are there in 9 4/5

2 answers:

6 0

To figure out tenths, first you need to convert the mixed number into a fraction so 9 and 4/5 becomes 45/5+4/5=49/5. Now you can convert this into tenths by multiplying both the numerator and denominator by 2, so then 49/5 becomes 98/10. So there are 98 tenths in the mixed number 9 and 4/5

Bingel [31]3 years ago

3 0

None, coz ur number doesnt even complete one 10

HAVE A NICE DAY ;)

You might be interested in

2 and one half divide by one fourth

solmaris [256]

Hi,

$2 \frac{1}{2} \div \frac{1}{4} \\ 2 \frac{2}{4} \div \frac{1}{4} = 10$

Hope this helps.
r3t40

3 0

4 years ago

claudia is making a gelatin desseert for a party.She plans on making 12 servings for every 5 people.If each pan claudia uses to

prisoha [69]

First we need to find the total amount of servings needed.

(x2) 12 servings/5 people (x2)
24 servings/10 people

Now we can find the amount of pans needed

24 servings/8 servings (1 pan)
=3 pans

She needs at least 3 pans

5 0

4 years ago

The value of y varies directly with x. When y = 25, x = 6 1/4. What is the value of y when x is 12? 4

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

if y = 25 when x = 6 1/4, then when y = 12, that would mean that we divided 25 by 2.0833. So we can do 6 1/4 divided by 2.0833 is the answer which is 3.00004800077.

(i think)

(probably wrong)

6 0

3 years ago

Write an equation for a parabola with x-intercepts (-4,0) and (5,0) which passes through the point (3. – 28).

Vanyuwa [196]

Answer:

y=a(x-p)(x-q)

y=a(x+2+√2)(x+2-√2)

passing through point (-1,1)

substitute

1=a(-1+2+√2)(-1+2-√2)

1=a(1+√2)(1-√2)

1=a(1-2)

1=a(-1)

a=1/(-1)

a=-1

y=-(x+[2+√2])(x+[2-√2])

y=-(x2+4x+2)

Thanks rate 5 stars

5 0

4 years ago

A drug used to relieve anxiety and nervousness has a half-life of 16 hours. if a doctor prescribes one 2.8-milligram every 24 ho

dlinn [17]

After 24 hours, 35.4% of the initial dosage remains on the body.

<h3>What percentage of the last dosage remains?</h3>

The exponential decay is written as:

$f(x) = A*e^{-k*x}$

Where A is the initial value, in this case 2.8mg.

k is the constant of decay, given by the logarithm of 2 over the half life, in this case, is:

$k = ln(2)/16h$

Replacing all that in the above formula, and evaluating in x = 24 hours we get:

$f(24h) = 2.8mg*e^{-24h*ln(2)/16h} = 0.9899 mg$

The percentage of the initial dosage that remains is:

$P = \frac{0.9899mg}{2.8mg}*100\% = 35.4\%$

If you want to learn more about exponential decays:

brainly.com/question/11464095

#SPJ1

8 0

2 years ago