If cos x = sin(20 + x)° and 0° < x < 90°, the value of x is what?
2 answers:
Answer:
<em>x=35°</em>
Step-by-step explanation:
If cos x = sin(20 + x)° and 0° < x < 90°, the value of x is 35°.
we can change cos to sin by saying cosx=sin(90-x)
now we drop sin and make the angles equal (nothing needs to be added or subtracted since its in the first quadrant)
90-x=20+x+k.360.......kEZ (k is an element of set of integers) (we say k.360 if it's cos and sin and k.180 if it's tan)
-x-x=20-90+k.360........kEZ
-2x=-70+k.360.........kEZ
divide all terms by -2
x=35-k.180.......kEZ
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