If cos x = sin(20 + x)° and 0° < x < 90°, the value of x is what?
2 answers:
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Answer:
y = 0.25x - 5
Step-by-step explanation:
Given line is 4x + y = 3
or y = -4x + 3
Comparing this with slope-intercept form y = mx + c :
slope of this line is -4
Product of slopes of perpendicular lines = -1
⇒ slope of a line perpendicular to this is =
= 0.25
This line also passes through the point (-4,-6)
The equation of a line having slope m and passing through a point (h,k) is
y - k = m(x - h)
⇒ equation of line perpendicular to given line is y - (-6) = 0.25×{x - (-4)}
⇒ y + 6 = 0.25×(x + 4)
⇒ y + 6 = 0.25x + 1
⇒ <u>y = 0.25x - 5</u>
This is in the slope-intercept form y = mx + c with slope m = 0.25 and y-intercept (0,-5)