8x-3(2x-4)=3(x-6) ?

Solve by using the square root method<br> (x-3)2 +4=125

AveGali [126]

Answer:

x= 127/2

Step-by-step explanation:

Let's solve your equation step-by-step.

(x−3)(2)+4=125

Step 1: Simplify both sides of the equation.

(x−3)(2)+4=125

(x)(2)+(−3)(2)+4=125(Distribute)

2x+−6+4=125

(2x)+(−6+4)=125(Combine Like Terms)

2x+−2=125

2x−2=125

Step 2: Add 2 to both sides.

2x−2+2=125+2

2x=127

Step 3: Divide both sides by 2.

2x/2 = 127/2

x=127/2

Please mark brainliest :)

3 0

3 years ago

What is the equation of the following line written in slope-intercept form?

ladessa [460]

Answer:

y = -2/3 x - 13/3

Step-by-step explanation:

We have one point at (-5,-1) and there is another point at (1,-5)

The slope is

m= (y2-y1)/(x2-x1)

= (-5--1)/(1--5)

= (-5+1)/(1+5)

= -4/6

=-2/3

The point slope form of the equation is

y-y1 = m(x-x1)

y--1 = -2/3(x--5)

y+1 =-2/3( x+5)

Distribute

y+1 = -2/3 x -10/3

Subtract 1 from each side

y +1-1 = -2/3 x -10/3 -1

Get a common denominator

y = -2/3 x -10/3 -3/3

y = -2/3 x - 13/3

6 0

3 years ago

Find the longer leg of the triangle.

Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

The length of the hypotenuse (the side opposite to the right angle) is given.
The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let $\text{Opposite}$ denotes the length of the side opposite to the $30^{\circ}$ acute angle, and $\text{Adjacent}$ be the length of the side next to this $30^{\circ}$ acute angle.

$\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}$ .

Similarly,

$\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}$ .

The longer leg in this case is the one adjacent to the $30^{\circ}$ acute angle. The answer will be $3$ .

There's a shortcut to the answer. Notice that $\sin{30^{\circ}} < \cos{30^{\circ}}$ . The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the $30^{\circ}$ angle will be the longer leg. There will be no need to find the length of the opposite leg.