Equation in point slope form of a line:
y-y₀=m(x-x₀)
m=slope
(x₀,y₀)=(-4,7)
m=2/3
y-7=(2/3)(x+4)
Answer: y-7=(2/3)(x+4)
the answer is 2 if you estimate to the tenths place
Answer:
400 ft
Step-by-step explanation:
Let the distance traveled = d
Let the time taken = t
d α t^2
d = kt^2
k = d /t^2
When d = 100 and t = 2.5secs
k = 100/ (2.5)^2
k = 16
d = 16t^2
When t = 5secs
d = 16(5)^2
d = 16 * 25
d = 400 ft
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
Answer:
Five more than the square of a number= 5 + x²
Five more than twice a number = 5 + 2x
Five less than the product of 3 and a number = 3x - 5
Five less the product of 3 and a number = 5 -3x
Twice the sum of a number and 5 = 2(x + 5)
The sum of twice a number and 5 = 2x + 5
The product of a cube of a number and 5= 5x³
The cube of the product of 5 and a number= (5x)³
