Given that question: Shyam invested money in the stock market. In the first
year, his stock increased 20%. He paid his stock broker $300 and then lost
$450. He withdrew $500, and then his remaining investment doubled. Shyam’s investment is now worth $7100. How much was Shyam’s original investment?
The solution is as follows:
Let the amount Shyam invested in the stock market be x, then in the first year his stock increased by 20% giving 1.2x.
He paid his stockbrocker $300 to have 1.2x - $300 left, and he lost $450 to have 1.2x - $300 - $450 = 1.2x - $750 left.
He withdrew $500 to have 1.2x - $750 - $500 = 1.2x - $1,250 left.
His remaining investment doubled to have 2(1.2x - $1,250) = 2.4x - $2,500
Shyam's investment is now worth $7,100 which means that
2.4x - $2,500 = $7,100
2.4x = $7,100 + $2,500 = $9,600
x = $9,600 / 2.4 = $4,000
Therefore, the value of Shyam's original investment is $4,000
Answer:
The first quartile is 26.
The third quartile is 45
The median is 30.5
The interquartile range is 19.
Hope that helped :)
Step-by-step explanation:
Answer: C. c+9/3
Step-by-step explanation:
You add the unknow varible C. with 9 and that sum is gong to be dived by 3 so 3 would be put on the bottom as the denominator.
Not sure what the question is, but this is 4/10 or 0.4.
A and C are equivalent expressions.
