The optimum shape of such a box is half a cube. The corresponding cube will have a volume of 2×256 ft³ = 512 ft³ = (8 ft)³. Such a box has a square base that is 8 ft on a side. If the height is half that of the cube, it will be 4 ft.
The dimensions of your box will be 8 ft square by 4 ft high.
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If the base dimension is x ft, the area (quantity of material) is
... a = x² + 4x(256/x²)
... a = x² + 1024x⁻¹
Then the derivative of area with respect to x is
... a' = 2x -1024x⁻²
Setting this derivative to zero and solving for x gives the value of x for minimum area.
... 0 = 2x -1024/x²
... 512 = x³
... x = 8 . . . . . . . . same as above.
The Eubanks Answer:
Step-by-step explanation:hehus
Answer:
n=16
Step-by-step explanation:
Two different things u can do
Substitution:
X-9y=12
+9y +9y
X=9y+12
-3(9y+12)+9y=36
-27y-36+9y=36
+36 +36
-18y = 72
/-18 /-18
Y = -4
Or whatever this other I’ve is called
-3x-9y=36
-1(X-9y)=(12)-1
-3x-9y=36
-x+9y=-12
-4x=24
X= -6
Y=44x+290
y=-28x+290
those are the first two
