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3 years ago

For each interval , decide if the average rate change is positive or negative

Mathematics

1 answer:

Talja [164]3 years ago

8 0

Answer:

well im not sure what your asking try asking it in different words

Step-by-step explanation:

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What are the solutions to the quadratic equ ton x2 – 16 = 0?

swat32

Answer:

x=4 and x=-4

Step-by-step explanation:

you dont really have to solve this one when you multiply the answer choices they should equal your B which is -16 and only 4 • -4 = -16 so yeah thats your answer

8 0

4 years ago

Would someone please help me with this pre final practice?

timofeeve [1]

Answer:

i think 5 so i say pick 5 because 19no 12no10 no so it 5

4 0

3 years ago

I'm not sure if D is right

Rzqust [24]

Ratio and proportion

height :legnth of shadow=56:49 (man's shadow)
we assume the ratio is the same for the tower thing (obelisk)

so
56:49=x:28
conver tto fraction
56/49=x/28
times both sides by 28
1568/49=x
32=x
answer is 32ft

5 0

3 years ago

Why is -16 the leading coefficient in quadratic applications

Lady bird [3.3K]

Answer:

Step-by-step explanation:e equation has a leading coefficient of 1 or if the equation is a difference of squares. The zero-factor property is then used to find solutions. ... Another method for solving quadratics is the square root property. The variable is squared.

3 0

3 years ago

Read 2 more answers

In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes

ale4655 [162]

Answer:

The sample mean is $\bar{x}=14.371$ min.

The sample standard deviation is $\sigma = 18.889$ min.

Step-by-step explanation:

We have the following data set:

$\begin{array}{cccccccc}0.15&0.82&0.81&1.44&2.70&3.28&4.00&4.70\\4.96&6.49&7.25&8.03&8.40&12.15&31.89&32.47\\33.79&36.80&72.92&&&&&\end{array}$

The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values.

The formula for the mean of a sample is

$\bar{x} = \frac{{\sum}x}{n}$

where, $n$ is the number of values in the data set.

$\bar{x}=\frac{0.15+0.82+0.81+1.44+2.7+3.28+4+4.7+4.96+6.49+7.25+8.03+8.4+12.15+31.89+32.47+33.79+36.80+72.92}{19}\\\\\bar{x}=14.371$

The standard deviation measures how close the set of data is to the mean value of the data set. If data set have high standard deviation than the values are spread out very much. If data set have small standard deviation the data points are very close to the mean.

To find standard deviation we use the following formula

$\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }$

The mean of a sample is $\bar{x}=14.371$ .

Create the below table.

Find the sum of numbers in the last column to get.

$\sum{\left(x_i - \overline{X}\right)^2} = 6422.0982$

$\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} } = \sqrt{ \frac{ 6422.0982 }{ 19 - 1} } \approx 18.889$

7 0

3 years ago