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umka21 [38]
3 years ago
12

Different sizes of ribbon need to be cut to go around various shapes for a craft project.

Mathematics
1 answer:
Dima020 [189]3 years ago
3 0

You have five numbers \sqrt{6},\ 2\dfrac{1}{2},\ -\sqrt{1},\ \dfrac{7}{2}, \ 3.\overline{3}.

Among them there is one negative number -\sqrt{1}, this number is smallest.

Note that

(\sqrt{6} )^2=6 \text{ and } \left(2\dfrac{1}{2}\right)^2=(2.5)^2=6.25.

Since 6.25>6, then

2\dfrac{1}{2}>\sqrt{6}

and these numbers are less than 3

Note that

\dfrac{7}{2}=3.5 \text{ and } 3.\overline{3}=3.333333....,

then 3.3333333... and these numbers are greater than 3.

Therefore, the correct order from the smallest to the greatest is:

-\sqrt{1}, \quad \sqrt{6},\quad 2\dfrac{1}{2},\quad 3.\overline{3}, \quad \dfrac{7}{2}.

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