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juin [17]
3 years ago
15

Use the discriminant to describe the roots of each equation. Then select the best description. x^2 + 9x + 14 = 0

Mathematics
1 answer:
NISA [10]3 years ago
7 0

B

given a quadratic equation in standard form

ax² + bx + c = 0

Then we can describe the nature of the roots using the discriminant

Δ = b² - 4ac

• if b² - 4ac > 0, then 2 real, distinct and irrational roots

• if b² - 4ac > 0 and a perfect square, then real and rational roots

• if b² - 4ac = 0, then real and equal roots

• if b² - 4ac < 0, then roots are not real

for x² + 9x + 14 = 0

with a = 1, b= 9 and c = 14, then

b² - 4ac = 9² - (4 × 1 × 14 ) = 81 - 56 = 25

Since b² - 4ac > 0 and a perfect square, then roots are real and rational


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Someone please help me thank you
Igoryamba

Answer:

x = - 1

Step-by-step explanation:

Given

4x = x^2 - 5               Transfer 4x to the right side.

Solution

x^2 - 4x - 5 = 0          Factor

(x - 5)(x + 1)

You want the negative solution. That means that the middle sign must be plus.

x + 1 = 0                   Subtract 10 from both sides

x = - 1                       Ten on the left disappears by the subtraction process.

Is that correct?

4x = x^2 - 5

x = - 10

4*(-1) = (-1)^2 - 5

-4  = ? 1 - 5

-4 = - 4

and it does work.  

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