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zlopas [31]
3 years ago
6

There are 240 students on Misty’s school. This is 5% of the total students in the school district. How many students are there i

n the school district?
Mathematics
1 answer:
Viktor [21]3 years ago
5 0
So if 240 is 5%, double it to get 480 than multiply it by 10 to get 4800.
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Five added to a number gives the sum of 39. what is the unknown number?
gregori [183]

Answer:

The unknown number is 34.

Step-by-step explanation:

x+5=39

x=39-5

x=34

6 0
4 years ago
Which expression represents the output when the input is m?
Tresset [83]
Uh can you show the problems? Because I wouldn’t be able to answer your question if you don’t show me the expressions
3 0
3 years ago
Manny is an online student who currently owns an older car that is fully paid for. He drives, on average, 110 miles per week to
Step2247 [10]

Answer:

The new car costs more

Old car = $5062.125

New car = $7161.357

Step-by-step explanation:

Manny drives an average of 110 miles per week with his old car. The old car gets 16 miles per gallon. The cost per gallon is $2.65 repair and Maintainance costs an average of $740 per year.

For the old car, to find the amount spent on the car we have

110/16 * 2.65 = $18.21875 / week

There are 52 weeks in a year. We have

10.21875*52 = $ 947.375

947.375 + 740

= $1687.375

= 1687.357 * 3

= $5062.125

The new car cost $6500 over a three year loan process.

The car gets 28 miles per gallon. It requires a maintenance f $10 per month. For the new car to find the amount, we have

110*28 * 2.65 *52 = $541.357

541.357 + 10(12) + 6500

= $7161.357

5 0
3 years ago
Use the figure and follow the directions below
Nataly_w [17]

Answer:

The answer is B

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
HELP ASAP!!! PLEASE CHECK ALL OF THEM!
pochemuha

Answer:

2.

A. (P+h)(x)

2x/x+4 (x-1) + x/x-1 (x+4)

2x^2-1/x^2-4

+

X^2+4/x^2-4

= 3x^2+3/x^2-4

B. (F-g)(x)

X^2-7x+6-x - 6

= x^2 -8x

C. (Fg)(x)

(X^2-7x+6)(x-6)

= x^3-13x^2+48x-36

D. (H/p)(x)

X/x-1 / 2x/x+4

X/x-1 / x+4/2x

= X^2+4x/2x^2-2x

3.

A. (F+g)(3)

X^2+1 + x-4

3^2+1 + 3-4

10 -1

= 9

B. (f-g)(0)

X^2+1 - x-4

0+1 -0-4

1-4

= -3

C. (Fg)(-k)

(X^2+1) (x-4)

(-k^2+1) (-k-4)

K^3+4k^2-k-4

D. (F/g)(k-2)

X^2+1 /x-4

K-2^2+1 / k-2 -2

= K^2-4k+5 / k-4

Step-by-step explanation:

8 0
3 years ago
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