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GenaCL600 [577]
3 years ago
11

Help! I don't get this

Mathematics
1 answer:
UNO [17]3 years ago
5 0
Bart because he lost the least
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A figure in the first quadrant is rotated 180 counterclockwise about the origin. Which quadrant will the rotated figure appear?
blagie [28]
I believe is quadrant 3
4 0
3 years ago
C/3=30/5 need help now
Zigmanuir [339]
30/5 is 6, so c/3 is 6, and c is 6x3, so c is 18.
7 0
3 years ago
Read 2 more answers
Find the sum of the following ap .1) 1/15, 1/12, 1/10,....,to 11 terms​
sertanlavr [38]

Answer:

33/20

Step-by-step explanation:

1/12 - 1/15 = 5/60 - 4/60 = 1/60

d = 1/60

a_n = a_1 + d(n - 1)

a_11 = 1/15 + (1/60)(11 - 1)

a_11 = 1/15 + 1/6

a_11 = 4/60 + 10/60

a_11 = 14/60

a_11 = 7/30

a_12 = 14/60 + 1/60

a_12 = 15/60

a_12 = 1/4

s_n = n(a_1 + a_n)/2

s_11 = 11(1/15 + 7/30)/2

s_11 = 11(2/30 + 7/30)/2

s_11 = 11(9/30)/2

s_11 = 99/60

s_11 = 33/20

8 0
3 years ago
Which functions have graphs that are less steep than the graph of f(x)= -4x^2
LiRa [457]
TTese are all parabolas   whose axis of symmetry  is the y  axis. The negative coefficient means they open downwards and the positive mean they open upwards. The higher the absolute value of the coefficient is the greater the slope, so  2x^2 will be steeper than x^2  and -4x^2 will be steeper than - 2x^2.

So h(x) and j(x)  are the answers.
8 0
3 years ago
Algebra II Help??? Subtracting Fractions<br><br> (2x)/(y^2-x^2) - (x)/(y-x)
denis23 [38]
Make bottom number same

ok, so remember
(a-b)(a+b)=a²+b²
so

to get from (y-x) to (y²-x²), multiply 2nd fraction by (y+x)

so multiply 2nd fraction by (y+x)/(y+x)
\frac{2x}{y^2-x^2}- \frac{(y+x)(x)}{y^2-x^2}=
\frac{2x-x(x+y)}{y^2-x^2}=
\frac{2x-x^2-xy}{y^2-x^2}
4 0
3 years ago
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