Answer:
a) x = 1225.68
b) x = 1081.76
c) 1109.28 < x < 1198.72
Step-by-step explanation:
Given:
- Th random variable X for steer weight follows a normal distribution:
X~ N( 1154 , 86 )
Find:
a) the highest 10% of the weights?
b) the lowest 20% of the weights?
c) the middle 40% of the weights?
Solution:
a)
We will compute the corresponding Z-value for highest cut off 10%:
Z @ 0.10 = 1.28
Z = (x-u) / sd
Where,
u: Mean of the distribution.
s.d: Standard deviation of the distribution.
1.28 = (x - 1154) / 86
x = 1.28*86 + 1154
x = 1225.68
b)
We will compute the corresponding Z-value for lowest cut off 20%:
-Z @ 0.20 = -0.84
Z = (x-u) / sd
-0.84 = (x - 1154) / 86
x = -0.84*86 + 1154
x = 1081.76
c)
We will compute the corresponding Z-value for middle cut off 40%:
Z @ 0.3 = -0.52
Z @ 0.7 = 0.52
[email protected] < x < [email protected]
-.52*86 + 1154 < x < 0.52*86 + 1154
1109.28 < x < 1198.72
123a
123q
123w
123e
123r
123t
123y
123u
123i
123o
123p
123s
123d
123f
123g
123h
123j
123k
I thought this would be easy lol, I tried, sorry for not getting an answer
Answer:
Step-by-step explanation:
0.3(n-5)=0.4-0.2
0.3(n-5) = 0.2
Dividing 0.3 both side
Answer:
150 (D)
Step-by-step explanation:
Answer: B. one-third
Step-by-step explanation:
Probability of picking a red marble, P(R) = 1/6
Probability of picking a yellow marble, P(Y) = 1/2
Therefore, the probability of picking a blue marble will be:
= 1 - (P(R) + P(Y))
= 1 - (1/6 + 1/2)
= 1 - (4/6).
= 1 - 2/3
= 1/3
The probability of picking a blue marble will be one third
