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Fittoniya [83]
2 years ago
15

K(x) = x^3 +2x^2-x-2 find all roots

Mathematics
1 answer:
Liono4ka [1.6K]2 years ago
3 0
<h2>The all roots are equation are 1, - 1 and - 2.</h2>

Step-by-step explanation:

The given cubic polynomial:

k(x) = x^3 + 2x^2 - x -2

To find, the all roots are x^3 + 2x^2 - x -2 = ?

∴ k(x) = x^3 + 2x^2 - x -2

⇒ x^3 + 2x^2 - x -2 = 0

⇒ x^2(x + 2) - 1(x + 2) = 0

⇒ (x^2 - 1)(x + 2) = 0

⇒ x^2 - 1 = 0 and x + 2 = 0

⇒ x^2 - 1 = 0

⇒ x^2 = 1

⇒ x = ± 1 = 1, - 1

or, x + 2 = 0

⇒ x = - 2

Thus, the all roots are equation are 1, - 1 and - 2.

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