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Fittoniya [83]
2 years ago
15

K(x) = x^3 +2x^2-x-2 find all roots

Mathematics
1 answer:
Liono4ka [1.6K]2 years ago
3 0
<h2>The all roots are equation are 1, - 1 and - 2.</h2>

Step-by-step explanation:

The given cubic polynomial:

k(x) = x^3 + 2x^2 - x -2

To find, the all roots are x^3 + 2x^2 - x -2 = ?

∴ k(x) = x^3 + 2x^2 - x -2

⇒ x^3 + 2x^2 - x -2 = 0

⇒ x^2(x + 2) - 1(x + 2) = 0

⇒ (x^2 - 1)(x + 2) = 0

⇒ x^2 - 1 = 0 and x + 2 = 0

⇒ x^2 - 1 = 0

⇒ x^2 = 1

⇒ x = ± 1 = 1, - 1

or, x + 2 = 0

⇒ x = - 2

Thus, the all roots are equation are 1, - 1 and - 2.

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Given an equation x+\frac{x}{7}+\frac{1}{11}\left(x+\frac{x}{7}\right)=60.

A statement that uses the equal sign to show that two expressions have the same value is called an equation. The equation is represented as ax+by=c.

Firstly, we will apply the distributive property to the given equation a×(b+c)=ab+ac, we get

x+\frac{x}{7}+\frac{x}{11}+\frac{x}{77}=60

Now, we will simplify the right-hand side equation by taking LCM, we get

\begin{aligned}\frac{77x+11x+7x+x}{77}&=60\\ \frac{96x}{77}&=60\end

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Hence, the solution of the given equation x+\frac{x}{7}+\frac{x}{11}+\frac{x}{77}=60 is x=48.125.

Learn more about solution of equation from here brainly.com/question/1477785

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