We need to find the expression for " number_of_prizes is divisible number_of_participants". Also there should not remain any remainder left. On in order words, we can say the reaminder we get after division is 0.
Let us assume number of Prizes are = p and
Number of participants = n.
If we divide number of Prizes by number of participants and there will be not remainder then there would be some quotient remaining and that quotent would be a whole number.
Let us assume that quotent is taken by q.
So, we can setup an expression now.
Let us rephrase the statement .
" Number of Prizes ÷ Number of participants = quotient".
p ÷ n = q.
In fraction form we can write
p/n =q ; n ≠ 0.
6x5+24x3+3x3+12x ------> Simplify by adding like terms
6x5 + 27x3 + 12x
The diagonals intersect perpendicularly, two consecutive angled are supplementary, and that opposite angles are equal
Answer:
5/8
Step-by-step explanation:
3/8 + 1/4
To add these fractions, you need a lowest common denominator. Both 4 and 8 "go into" 8, so the lowest common denominator is 8.
In order to change the denominator 4 to 8, you need to multiply both the numerator and the denominator by 2. So, 1/4 becomes 2/8.
Now, the problem is 3/8 + 2/8.
You can add the numerators, because the denominator is the same for each fraction.
3/8 + 2/8 = 5/8
Answer: 15
Step-by-step explanation:
