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kirza4 [7]
3 years ago
13

G the population of a town today is 48000 people. if the population decreases with a constant rate of change and the decrease is

4% in the first year, what will the town's population be in 10 years?
Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0
The population in ten years will be 208,000
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4 x 4/12=<br> Sheeeeeeeeeeeeeeeesh
Crazy boy [7]

Answer:

1.3 or \frac{13}{10}

Hope this helps!

6 0
3 years ago
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If –y + 2x^2 – x = -5y^3 then find dy / dx in terms of x and y.
vlada-n [284]

Answer:

dy/dx = \frac{4x-1}{1-15y^{2} }

Step-by-step explanation:

-y + 2x²- x = -5y³

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4x - 1 = dy/dx - 15y².dy/dx

dy/dx(1 - 15y²) = 4x - 1

dy/dx = \frac{4x-1}{1-15y^{2} }

8 0
3 years ago
how do I cancel this out??? this is the only thing I don't understand... have an a on my class but... never get these right...
Rus_ich [418]
You factor the expression first leaving you with \frac{3xy(z-1)}{3xy}
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3 years ago
With a capacity of 6,300 people, Royal Caribbean’s Oasis of the Seas is the world’s largest cruise ship. The average beer consum
Mariulka [41]

Step-by-step explanation:

Mean = 81740

Standard deviation = 4590

Sample size = 15

Alpha level = 1-0.95 = 0.05

Df = 15-1 = 14

Critical value:

alpha/2 = 0.05/2 = 0.05

t0.025

t critical value = 2.145

Margin of error ME

2.145 x 4590/√15

2.145 x 4590/3.873

ME = 2542.09

Confidence interval

Lower CI = mean - ME

= 81740-2542.09

= 79197.91

Upper CI = mean + ME

= 81740+2542.09

= 84282.09

[ 79197.91, 84282.09]

B.

Using excel, exact answer for CI

Lower limit = 79198.142724212173

Upper limit = 84281.8572757827

C.

The assumptions to be made from the population are that

1. Samples are random

2. These samples are gotten from an approximately normal distribution

6 0
3 years ago
I need help with this problem ASAP
Kamila [148]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
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