3[x+3(4x-5)]=15x-24; x+12x-15=5x-8 (divide both sides by 3); 8x=7 (move all the x's to one side), x=7/8
Answer: <span><span>2x² + x - 2</span> (the first option)
Explanation:
1) Question: divide 8x⁴+2x³-7x²+3x-2 by 4x² - x + 1
2) First term of the quotient
</span><span> 8x⁴ + 2x³ - 7x² + 3x - 2 | 4x² - x + 1
---------------------
-8x⁴ + 2x³ - 2x² 2x²
----------------------------------
4x³ - 9x² + 3x - 2
3) Second term of the quotient:
</span>
<span> 8x⁴ + 2x³ - 7x² + 3x - 2 | 4x² - x + 1
---------------------
-8x⁴ + 2x³ - 2x² 2x² + x
----------------------------------
4x³ - 9x² + 3x - 2
-4x³ + x² - x
----------------------------
- 8x² + 2x - 2
4) third term of the quotient:
</span>
<span> 8x⁴ + 2x³ - 7x² + 3x - 2 | 4x² - x + 1
---------------------
-8x⁴ + 2x³ - 2x² 2x² + x - 2
----------------------------------
4x³ - 9x² + 3x - 2
-4x³ + x² - x
----------------------------
- 8x² + 2x - 2
8x² - 2x + 2
-------------------------
0
5) Conclusion: since the remainder is 0, the division is exact and the quotient is </span>2x² + x - 2
You can verify the answer by multiplying the quotient obtained by the divisor. The result has to be the dividend.
In this question, we're trying to find the inequality that is true.
To find your answer, we can convert the numbers in the absolute value:
|−5| < 4:
5 < 4 <em>false</em>
|−4| < |−5|:
4 < 5 <em>true </em>
|−5| < |4|
5 < 4 <em>false</em>
|−4| < −5
4 < -5 <em>false</em>
The only true inequality here would be |−4| < |−5|, since it works with the inequality sign.
Answer:
|−4| < |−5|
