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3 years ago

Can someone please help answer this for me??

Mathematics

1 answer:

liberstina [14]3 years ago

8 0

The mean is the average of the numbers .To calculate it just add up all the numbers, then divide by how many numbers there are in total.

The number which appears most often is the mode.

To find the Median, place the numbers you are given in value order and find the middle number

To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

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today reza ate 20 grapes which is 400% as many grapes as he ate yesterday. explain how to use equal ratios to find the number of

Darina [25.2K]

Answer:

Write 400% as the ratio 400/100. To find an equivalent ratio, you know that 400 divided by 20 is 20, so 100 divided by 20 will give you the answer. 100 ÷ 20 = 5. Reza ate 5 grapes yesterday.

Brainliest please!

7 0

2 years ago

Read 2 more answers

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

2 years ago

30 points please help on these questions!

hichkok12 [17]

Answer:

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5 0

2 years ago

If RH = 10 units, HT = 16 units, and GH = 8 units, what is the length of line segment HJ?

Dominik [7]

Answer:

$HJ=20\ units$

Step-by-step explanation:

The complete question is

RT and GJ are chords that intersect at point H. If RH = 10 units, HT = 16 units, and GH = 8 units, what is the length of line segment HJ? 18 units 20 units 26 units 28 units

we know that

The intersecting chords theorem is a statement that describes a relation of the four line segments created by two intersecting chords within a circle. It states that the products of the lengths of the line segments on each chord are equal

In this problem

$(RH)(HT)=(GH)(HJ)$