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FrozenT [24]
3 years ago
5

Meiko is hanging a picture collage on her wall. The dimensions of the collage are shown in the diagram. She plans to cover

Mathematics
2 answers:
alexira [117]3 years ago
5 0

Answer: \frac{A_{collage}}{15.75\ in^2}

Step-by-step explanation:

Since you did not attach the diagram and I don't know the dimensions of the collage, I will give you a general explanation of the procedure you need to use in order to solve the exercise:

1. You need to use the formula for calculate the area of a rectangle:

A=lw

Where "l" is the length and "w" is the width.

2. Using the formula, you must calculate the area of an small picture.

You know that its length is 4.5 inches and its width is 3.5 inches. Therefore, its area is:

A_{picture}=(4.5\ in)(3.5\ in)\\\\A_{picture}=15.75\ in^2

3. Calculate the area of the collage using the formula:

A_{collage}=(l_{collage})(w_{collage})

4. Finally, divide the area of the collage by the area of an small picture in order to find the number of small pictures that will fit within the collage:

\frac{A_{collage}}{15.75\ in^2}

ddd [48]3 years ago
4 0

Answer:

C is the answer

Step-by-step explanation: I took a test

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Step-by-step explanation:

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3 years ago
Suppose that the mean time that visitors stay at a museum is 94.2 minutes with a standard deviation of 15.5 minutes. The standar
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Answer:

94.2 -0.994*3.1 = 91.1186

94.2 +0.994*3.1 = 97.2814

And the 68% confidence interval is given by (91.1186, 97.2814)

Step-by-step explanation:

For this case we know that mean time that visitors stay at a museum is given by:

\bar X = 94.2

The standard deviation is given by:

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And the standard error is given by:

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And we want to interval captures 68% of the means for random samples of 25 scores and for this case the critical value can be founded like this using the normal standard distribution or excel:

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We can find the interval like this:

\bar X \pm ME

And replacing we got:

94.2 -0.994*3.1 = 91.1186

94.2 +0.994*3.1 = 97.2814

And the 68% confidence interval is given by (91.1186, 97.2814)

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