All categories

3 years ago

Meiko is hanging a picture collage on her wall. The dimensions of the collage are shown in the diagram. She plans to cover

Mathematics

2 answers:

alexira [117]3 years ago

5 0

Answer: $\frac{A_{collage}}{15.75\ in^2}$

Step-by-step explanation:

Since you did not attach the diagram and I don't know the dimensions of the collage, I will give you a general explanation of the procedure you need to use in order to solve the exercise:

1. You need to use the formula for calculate the area of a rectangle:

$A=lw$

Where "l" is the length and "w" is the width.

2. Using the formula, you must calculate the area of an small picture.

You know that its length is 4.5 inches and its width is 3.5 inches. Therefore, its area is:

$A_{picture}=(4.5\ in)(3.5\ in)\\\\A_{picture}=15.75\ in^2$

3. Calculate the area of the collage using the formula:

$A_{collage}=(l_{collage})(w_{collage})$

4. Finally, divide the area of the collage by the area of an small picture in order to find the number of small pictures that will fit within the collage:

$\frac{A_{collage}}{15.75\ in^2}$

ddd [48]3 years ago

4 0

Answer:

C is the answer

Step-by-step explanation: I took a test

You might be interested in

The ____ allows you to use pattern-matching characters to determine whether one string is equal to another string.

romanna [79]

The <u>like operato</u>r allows you to use pattern-matching characters to determine whether one string is equal to another string.

plz give me brainly

6 0

3 years ago

Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation: 22, 18, 1

BigorU [14]

Answer:

a: Sample mean: 20, Sample standard deviation: 1.732

b: 19.13 <µ < 20.87

c: 18.84< µ < 21.16

d: as the confidence level increases, the interval becomes wider

Step-by-step explanation:

a: Sample mean is found by adding up all the individual values of the sample, then dividing by the total number of values in the sample.

Sample standard deviation is the square root of the variance

See the first attached photo for the calculations of these values.

We need to create a 80% confidence interval for the population. Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.

Look for the column on the t-distribution chart that has "area in two tails" of 0.20 (80%), and row 7 (degree of freedom)

The t-value is 1.415

See the second attached photo for the construction of the confidence interval

We need to create a 90% confidence interval for the population. Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.

Look for the column on the t-distribution chart that has "area in two tails" of 0.10 (90%), and row 7 (degree of freedom)

The t-value is 1.895

See the third attached photo for the construction of the confidence interval

3 0

3 years ago

Istanbuldaki marmaray hattında tren maksimum 100km/sa'tir Trenin saniyedeki hızı kaç m/sn'dir

Tanzania [10]

Answer:

27,77

1 saatte 3600 saniye var

100 km de 100.000 metre yapar o halde

100.000/3600 = 27,77 m/sn yapar

alıntıdır (◍•ᴗ•◍)

7 0

3 years ago

The half-life of cesium-137 is 30 years. Suppose we have a

VMariaS [17]

(a) If $y(t)$ is the mass (in mg) remaining after $t$ years, then $y(t) = y(0) e^{kt}=100e^{kt}.$

$y(30) = 100 e^{30k} = \frac{1}{2}(100) \implies e^{30k} = \frac{1}{2} \implies k = -(\ln 2) /30 \implies \\ \\
y(t) = 100e^{-(\ln 2)t/30} = 100 \cdot 2^{-t/30}$

(b) $y(100) = 100 \cdot 2^{-100/30} \approx \text{9.92 mg}$

(c)
$100 e^{- (\ln 2)t/30} = 1\ \implies\ -(\ln 2) t / 30 = \ln \frac{1}{100}\ \implies\ \\ \\
t = -30 \frac{\ln 0.01}{\ln 2} \approx \text{199.3 years}$

3 0

3 years ago

A cafe offers 3 sides with the lunch special. A customer can choose from rice, green beans, carrots, salad, and corn. How many d

elena-14-01-66 [18.8K]

12, because 3 times 4 is 12.

5 0

3 years ago

Read 2 more answers