ABC is a equilateral triangle .
Proof :-
Let's assume both circles as C1 and C2 [ as shown in the figure ]
AC is the radius of circle C1.
BC is the radius of circle C2 .
AB and AC both are radius of circle C1 so both are equal ie AB = AC .
AB and BC both are radius of circle C 2 so both are equal ie AB = BC .
Hence we conclude that .
AB = BC = AC.
So the triangle is equilateral triangle.
Answer:
Following are the solution to the given points:
Step-by-step explanation:
Given values:
Total staff=40
In point a:
To calculate the median number first we arrange the value into ascending order and then collect the even numbers of calls that were also made. Its average of the middle terms is thus the median.
The midterms =55 and 59 so,
Median =
In point b:
First-quarter
The first quarterlies are
therefore the multiply of 0.5 by calculating the difference of the 7th and 8th term are:
therefore the it is multiply by the 0.5 for the difference of the 22nd and 23rd term:
In point c:
First decile
In point d:
quartiles are:
The right answers for the decile are:
As for will be available.