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Harrizon [31]
3 years ago
5

A circle has a sector with area \dfrac{64}{5}\pi 5 64 ​ πstart fraction, 64, divided by, 5, end fraction, pi and central angle o

f \purple{\dfrac{8}{5}\pi} 5 8 ​ πstart color #9d38bd, start fraction, 8, divided by, 5, end fraction, pi, end color #9d38bd radians . What is the area of the circle?
Mathematics
1 answer:
Marina86 [1]3 years ago
8 0

Answer:

Area of circle is \dfrac{1024\:\pi}{25}

Step-by-step explanation:

Since angle \theta is given in radians, so using formula for area of sector in radians is given as,

Area\:of\:sector=\dfrac{1}{2}\:r^{2}\:\theta

Given area of sector and angle. Therefore substituting the values in above formula,

\dfrac{64\pi}{5}=\dfrac{1}{2}\:r^{2}\:\left (\dfrac{8\pi}{5}\right )

Cancelling out the common term,

16=\dfrac{1}{2}\:r^{2}

Multiplying with 2 on both sides,

16=r^{2}

Therefore value of r^{2} is 16

Formula for area of circle is,

Area\:of\:circle=\pi\:r^{2}

Substituting the value,

Area\:of\:circle=\pi\times16

Area\:of\:circle=16\pi

Therefore area of circle is 16\pi

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Answer:

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Step-by-step explanation:

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Hence, (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 ⇒ x^{3}+2x^{2} -19x -20

x^{3}+2x^{2} -19x -20  = (x+1)(x^{2} +x-20)

First,

x^{2} +x-20 = x^{2} +5x-4x-20\\x^{2} +5x-4x-20= x(x+5)-4(x+5)\\x(x+5)-4(x+5) = (x-4)(x+5)

∴ (x+1)(x^{2} +x-20) = (x+1)(x-4)(x+5)

Hence, X^3+2x^2-19x-20 = (x+1)(x-4)(x+5)

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