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Arisa [49]
3 years ago
5

Simplify -16 -22+ 22) A. -16 B. 39 C. 16 D.38 Help me PLZZZZZZ ;(

Mathematics
2 answers:
Alina [70]3 years ago
8 0

Answer:

A

Step-by-step explanation:

-22+22=0

-16

vlabodo [156]3 years ago
4 0

Answer: A

-16 is the answer

Plz mark brainliest:)

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The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for hou
o-na [289]

This question s incomplete, the complete question is;

The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for 15 hours. The Thompson family's sprinkler was used for 30 hours.

There was a combined total output of 1050 of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour  

Answer:

The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr

Step-by-step explanation:

Given the data in the question;

let water p rate for Watson family and the Thompson family sprinklers be represented by x and y respectively

so

x + y = 55  ----------------equ1

x = 55 - y ------------------qu2

also

15x + 30y = 1050

x + 2y = 70 --------------equ3

input equ2 into equ3

(55 - y) + 2y = 70

- y + 2y = 70 - 55

y = 15

input value of y into equ1

x + 15 = 55

x = 55 - 15

x = 40

Therefore, The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr

8 0
3 years ago
The A&M Hobby Shop carries a line of radio-controlled model racing cars. Demand for the cars is assumed to be constant at a
Bond [772]

Answer:

Step-by-step explanation:

A) Demand per month= 40 cars

Annual Demand (D)= 12*40 = 480

Fixed Cost per order (K)= 15

Holding Cost= 20% of cost= 60 *0.2 = 12

a. Economic Order Quantity=

Q^{*}={\sqrt {{\frac {2DK}{h}}}}

= √(2*480*15)/12

=34.64 ~ 35

Total Cost =P*D+K(D/EOQ)+h(EOQ/2) P= Cost per unit

= 60*480+ 15(480/35) + 12(35/2)

= 28800+ 205.71+ 210

=$29215.71

B). Backorder Cost (b)= $45

Qbo= Q* × √( b+h/ h)

= 35*√(12+45/ 45)

= 35* 1.12

=39.28 ~ 39

Shortage (S)= Qbo * (K/K+b)

= 39* (15/15+45)

= 39* 0.25

= 9.75

Total Cost Minimum=( bS2/ 2Qbo) + P (Qbo- S)2/2Qbo + K(D/Qbo)

=45* 9.752 / 2* 392 + 60 (39-9.75)2/ 2* 392 + 15 ( 480/39)

= 1.40+ 21.9.+ 184.61

=$207.91

C)Length of backorder days (d) = Demand ÷ amount of working days

d = 480 ÷ 300

d = 1.6

Calculate the backorders as the maximum number of backorders divided by the demand per day

s/d = 9.75/1.6 = 6.09 days (answer)

D) Calculate the difference in total between not using backorder:

$207.85 + $207.85 - 207.91 = $207.79

The saving in using backorder is $207.79.

Therefore I would recommend using a backorder

6 0
2 years ago
A large farm has 75 acres of wheat and 62.5 acres of corn. The farm crew can harvest the wheat from 12 acres and the corn from 1
MAVERICK [17]
The answer for either field being harvested is 6.25 days (acres/(rate of harvest))
The answer is probably seven because, even though a day can be divided into parts, the fields are done the seventh not the sixth. (I'm assuming the problem calls for whole days)
4 0
2 years ago
If 4 more than 4 times a certain number is the same as 4 more than the product of 3 and 4, what is that number?
gtnhenbr [62]

Answer: the number is 3

Step-by-step explanation:

Let the number be represented by x.

If 4 more than 4 times a certain number is the same as 4 more than the product of 3 and 4, it means that

4x + 4 = 4 + 3×4

4x + 4 = 4 + 12

4x + 4 = 16

Subtracting 4 from the left hand side and the right hand side of the equation, it becomes

4x + 4 - 4 = 16 - 4

4x = 12

Dividing the left hand side and the right hand side of the equation by 4, it becomes

x = 12/4 = 3

5 0
2 years ago
What is another way to write 0.7
Alekssandra [29.7K]
.7 is the answer to your question


4 0
3 years ago
Read 2 more answers
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