Answer
The scale factor is
Explanation
We have to ways to find the scale factor here:
1. Find the unit fraction from inches to miles; in other words, we need to divide the distance between the cities on the map (in inches) by the actual distance between the cities.
We can conclude that the scale factor is
2. Let be the scale factor.
We know form our problem that 24 miles times the scale factor is equal 4 1/2 inches, so we can set up an equation an solve for :
Just like before, we can conclude that the scale factor is
B.
Answer
6 inches separate the cities on the map
Explanation
We know that our scale factor is 1/4 inch = 1 mile, so we can create a conversion factor to convert 24 miles to inches. Since we need to convert from miles to inches, the denominator of our conversion factor must be 1 mile so we can cancel miles out. Notice that we can also express 1/4 inch as 0.25 inch to simplify our calculations:
We can conclude that if the conversion factor is 1/4 inch = 1 mile, 6 inches separate the cities on the map.
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<span>4 ⋅ 6 + 5 ⋅ 7 + 6 ⋅ 8 + ... + 4n( 4n + 2) = 4(4n+1)(8n+7)/6
is false because it isn't even true when n=1.
4 ⋅ 6 = 4(4*1+1)(8*1+7)/6
24 = 4(5)(15)/6
24 = 50
Also 4n(4n+2) is not even the correct formula
for the nth term. The correct nth term formula
of 4 ⋅ 6 + 5 ⋅ 7 + 6 ⋅ 8 + ...
is (n+3)(n+5). So it's wrong all the way around.</span>
Answer:
- after week 7: 4374 pennies
- 486 pennies: after week 5
Step-by-step explanation:
The sequence values have a first term of 6 and a common ratio of 3, so can be described by the formula ...
an = 6·3^(n-1)
This can be rearranged to ...
an = 2·3^n
__
When n=7, the value is ...
a7 = 2·3^7 = 4374 . . . . pennies saved after 7 weeks
__
To find when there are 486 pennies saved, we can solve the equation ...
486 = 2·3^n
243 = 3^n
log(243) = n·log(3) . . . . . . . take the logarithm
log(243)/log(3) = n = 5 . . . . divide by the coefficient of n
Tabitha will have saved 486 pennies after 5 weeks.
2 (an - 1) = 40
2an - 2 =40
2an = 40 - 2
2an = 38
2an/2 = 38/2
an = 19
THEY ARE ALWAYS PARALLELOGRAMS
