In order to solve or know the probability of having 2 girls
and 2 boys, assumed that a girl is as likely as a girl at each birth, pascal’s
triangle will be likely used. And we will be referring to the line 4 of pascal’s
triangle, which was 1 4 6 4 1. Then it
will look like this: 1 = 4 girls; 4 = 3 girls & 1 boy; 6 = 2 girls & 2
boys; 4 = 3 boys & 1 girl; 1 = 4 boys. And now for the solution in order to
get the probability of having 2 girls and 2 boys is to divided into the sum of 1+4+6+4+1.
6) subtract 16 on both sides
then it should be x/4>18
then you would times 18 by 4 and get
c as the answer
7) the answer is d.
because 52-12 is 40 and 52/4 is 13
Answer:
that is the solution to the question
Answer:
c = 21
Step-by-step explanation:
<u>**I assume that side WX in my diagram (attached as an image below) is the value of C that we're looking for. ALSO, the sizes and lengths of the parallelograms are NOT to scale.**</u>
If two parallelograms are similar, that means the lengths of the corresponding sides have EQUAL ratios.
PL corresponds with WZ. To get from 15 to 45, you would multiply 15 by 3, so the ratio of the legnths of the corresponding sides between these two parallelograms is 1:3.
With that in mind, we can apply this ratio to find WX.
We know that AP has a length of 7, so we will multiply that by 3, getting a value of 21, and 7:21 ratio is the same as 1:3.
c = 21
Hope this helps (●'◡'●)