Evaluate f(-2) if f(x) = x+3

Hi please HELP ME I really need it

earnstyle [38]

Answer:

? = 14

Step-by-step explanation:

let us say that ? = x

7^x * 7^5^4 = 7^34

When you have a power to a power you multiply

7^x * 7^20 = 7^34

when you multiply common bases you add the power. since all the bases aer the same just look at the power

7^34-20 = 7^x

7^14 = 7^x

6 0

3 years ago

Which of the following shows the additive inverse of 4?*

spayn [35]

C is the correct answer I think

3 0

3 years ago

If w = 2, x = 3, y = 5, and z = 6 then evaluate the expression: z/2

galina1969 [7]

Answer:

3

Step-by-step explanation:

To evaluate the expression, we have to substitute the variable in the expression, z, for its stated value. Given that z = 6, substitute 6 for the z in the expression and solve:

$\frac{z}{2} \\= \frac{6}{2} \\= 3$

Thus, the answer is 3.

7 0

3 years ago

Need to know the area of the composite figure.

MariettaO [177]

Answer:

Step-by-step explanation:

you can figure out the area by using two formulas: area of a circle (on each end are two semi circles which when combined, make a circle) and area of a rectangle

Acircle: pi(r^2) = pi(5^2) = 25pi

Arectangle: length*width = 20*10 = 200ft^2

area of composite figure: (25pi ft^2) + 200ft^2

4 0

4 years ago

The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales

andrezito [222]

Answer:

$t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657$

$p_v =P(t_{(39)}>6.657)=3.17x10^{-8}$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=44$ represent the sample mean

$s=1.9$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =42$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 42, the system of hypothesis would be:

Null hypothesis: $\mu \leq 42$

Alternative hypothesis: $\mu > 42$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>6.657)=3.17x10^{-8}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.

3 0

3 years ago