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3 years ago

How can I express this as a single power with positive exponents?

Mathematics

1 answer:

Tamiku [17]3 years ago

3 0

Answer:

5^1

Step-by-step explanation:

$\sqrt{5} =5^{\frac{1}{2} }$ (law of indices - fractional powers)

after converting all the numbers to this form:

$\frac{5^{{\frac{2}{3} } } * 5^{\frac{1}{2} } }{5^{\frac{1}{6} } } \\$

combine using law of indices:

5^(2/3+1/2-1/6) = 5^1

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Find the gradient of the line segment between the points (4,-3) and (5,-6).

frez [133]

Answer: 3

Step-by-step explanation:

$Formula: \frac{y2 - y1}{x2 - x1}$

Plug the numbers into the formula:

$\frac{-6 - -3}{5-4}$ -> $\frac{-6+3}{5-4}\\$

Reduce:

$\frac{3}{1} = 3$

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3 years ago

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3 years ago

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3 years ago

In a box there are n red marbles and three times as many black marbles. There are 36

KATRIN_1 [288]

Answer:

it is 12

Step-by-step explanation:

for n= 36 divided by 3.

7 0

3 years ago

A record club has found that the marginal profit,

tankabanditka [31]

Solution :

Given :

$P'(x) = -0.0008x^3+0.20x^2+46.8x,$ for x ≤ 200

Total profit when 120 members are enrolled is :

$\sum_{i=1}^6P'(x_i) \Delta x$ with $\Delta x = 20$

Using the left end points, we get,

The values of $x_i$ are : { 0, 20, 40, 60, 80, 100}

Therefore,

$P'(x_1) = P'(0)=-(0.0008)(0)^3+(0.20)(0)^2+(46.8)(0)$

= 0

$P'(x_2) = P'(20)=-(0.0008)(20)^3+(0.20)(20)^2+(46.8)(20)$

= 1009.6

$P'(x_3) = P'(40)=-(0.0008)(40)^3+(0.20)(40)^2+(46.8)(40)$

= 2140.8

$P'(x_4) = P'(60)=-(0.0008)(60)^3+(0.20)(60)^2+(46.8)(60)$

= 3355.2

$P'(x_5) = P'(80)=-(0.0008)(80)^3+(0.20)(80)^2+(46.8)(80)$

= 4614.4

$P'(x_6) = P'(100)=-(0.0008)(100)^3+(0.20)(100)^2+(46.8)(100)$

= 5880

$\sum_{i=1}^6P'(x_i) \Delta x = P'(x_1)\Delta x + P'(x_2)\Delta x + P'(x_3)\Delta x + P'(x_4)\Delta x + P'(x_5)\Delta x + P'(x_6)\Delta x$

= (0)(20) + (1009.6)(20) + (2140.8)(20) + (3355.2)(20) + (4614.4)(20) + (5880)(20)

= (20)( 0 + 1009.6 + 2140.8 + 3355.2 + 4614.4 + 5880)

= (20)(17,000)

= 340,000 cents

$=\frac{340000}{100} \ \text{dollars}$

= 3400 dollars

Hence, the required total profit is 3400 dollars.

8 0

3 years ago