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Novosadov [1.4K]
3 years ago
14

How can I express this as a single power with positive exponents?

Mathematics
1 answer:
Tamiku [17]3 years ago
3 0

Answer:

5^1

Step-by-step explanation:

\sqrt{5} =5^{\frac{1}{2} } (law of indices - fractional powers)

after converting all the numbers to this form:

\frac{5^{{\frac{2}{3} }  } *  5^{\frac{1}{2} } }{5^{\frac{1}{6} } } \\

combine using law of indices:

5^(2/3+1/2-1/6) = 5^1

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The answer is B.about 400, because if you multiply 18 by 24 you get the answer without rounding, and that answer would be 434; once 434 is rounded to the closest possible answer, you get that the answer, which is, as stated before, B. about 400.
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3 years ago
Express 0.032 as a fraction in lowest terms
SIZIF [17.4K]

Answer:

4/125

Step-by-step explanation:

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2 years ago
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For the following right triangle, find the side length of x. round your answer to the nearest hundredth.
tatyana61 [14]

Answer:

14.87 units

Step-by-step explanation:

The sides of all right triangles share the same relationship known as the Pythagorean Theorem a² + b² = c². Substitute the lengths of the triangle into the theorem and solve for the unknown side. Since the problem does have an attached a picture, assume that a = 10, b = 11, and c = x.

10² + 11² = x²

100 + 121 = 221²

221 = x²

√221 = √x²

14.87 = x

6 0
2 years ago
For each of the following, state the equation of a perpendicular line that passes through (0, 0). Then using the slope of the ne
SVEN [57.7K]

Answer:

The answer is below

Step-by-step explanation:

a) y=3x-1

The standard equation of a line is given by:

y = mx + c

Where m is the slope of the line and c is the intercept on the y axis.

Given that y=3x-1, comparing with the standard equation of a line, the slope (m) = 3, Two lines with slope a and b are perpendicular if the product of their slope is -1 i.e. ab = -1. Let the line perpendicular to y=3x-1 be d, to get the slope of the perpendicular line, we use:

3 × d = -1

d = -1/3

To find the equation of the perpendicular line passing through (0,0), we use:

y-y_1=d(x-x_1)\\d\ is\ the \ slope:\\y-0=-\frac{1}{3} (x-0)\\y=-\frac{1}{3}x

To find  x if the point P(x, 4) lies on the new line, insert y = 4 and find x:

y=-\frac{1}{3}x\\ 4=-\frac{1}{3}x\\-x=12\\x=-12

b) y=1/4 x+2

Given that y=1/4 x+2, comparing with the standard equation of a line, the slope (m) = 1/4. Let the line perpendicular to y=1/4 x+2 be f, to get the slope of the perpendicular line, we use:

1/4 × f = -1

f = -4

To find the equation of the perpendicular line passing through (0,0), we use:

y-y_1=f(x-x_1)\\f\ is\ the \ slope:\\y-0=-4 (x-0)\\y=-4x

To find  x if the point P(x, 4) lies on the new line, insert y = 4 and find x:

y=-4}x\\ 4=-4x\\x=-1

8 0
2 years ago
A circle with radius of 4 cm sits inside a circle with radius of 11 cm.
kap26 [50]

The area of the shaded region = 330 sq cm

Step-by-step explanation:

Given,

The radius of small circle (r) = 4 cm

The radius of large circle (R) = 11 cm

To find the shaded region

Formula

The area of circle of radius r = πr^{2} sq cm

So, The radius of the small circle = π×4^{2} sq cm = 16π sq cm

The radius of the large circle = π×11^{2} sq cm = 121π sq cm

Hence the area of the shaded region = 121π-16π sq cm

= 105π sq cm

= 105 × \frac{22}{7} sq cm = 330 sq cm

5 0
3 years ago
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