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Ne4ueva [31]
4 years ago
9

Tim has $20 to buy snacks for 12 people in an office. Each person will get one snack. Tim is buying bags of pretzels that cost $

1.50 per bagand bags of crackers that cost $2.00 per bag.
how many bags of pretzels will tim buy?
Mathematics
1 answer:
Greeley [361]4 years ago
4 0

Answer:

  8 bags of pretzels

Step-by-step explanation:

Let x represent the number of bags of pretzels Tim buys. We assume he spends exactly $20 on exactly 12 bags of snack food. Then his purchase is ...

  1.50x + 2.00(12-x) = 20.00

  -0.50x +24.00 = 20.00 . . . eliminate parentheses, collect terms

  -0.50x = -4.00 . . . . . . . . . . .subtract 24

  x = 8 . . . . . . . . . . divide by -0.50

Tim will buy 8 bags of pretzels.

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Damm [24]

The weight average of the coordinates is -4

<h3>How to determine the weight average?</h3>

The complete question is given as:

The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. And we need to calculate the weight average

The given parameters are:

  • Coordinate -6 has a weight of 3
  • Coordinate 2 has a weight of 1.

The weight average is then calculated as:

Weight average = Sum of (Weigh * Coordinate)/Sum of Weights

So, we have:

Weight average = (-6 * 3 + 2 * 1)/(3 +1)

Evaluate the products

Weight average = (-18 + 2)/(3 +1)

Evaluate the sum

Weight average = -16/4

Evaluate the quotient

Weight average = -4

Hence, the weight average of the coordinates is -4

Read more about average at

brainly.com/question/20118982

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<u>Complete question</u>

The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. Calculate the weight average

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2 years ago
What are the odds of spinning blue? 1/3 1/2 1/5 1/4
aleksandr82 [10.1K]

Answer:

p(blue) = 1/3

Step-by-step explanation:

There are 2 blue circles out of the 6 total circles

P(blue) = blue/total

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I will make the right answer the brainliest, no lie.
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Solution

If point P is equidistant from the vertices of ΔDEF, the segment PE must measure the same that the segment PF, then these two segments are congruent:

PE=PF

Then ΔEFP is an isisceles triangle, because it has two congruent sides (PE=PF), and the height of the side EF (PJ perpendicular to EF) divides ΔEFP into two congruent right triangles (ΔEJP and ΔFJP). The legs EJ and FJ must be congruent:

FJ=EJ

3x-1=x+3

Solving for x: Subtracting x and adding 1 both sides of the equation:

3x-1-x+1=x+3-x+1

2x=4

Dividing both sides of the equation by 2:

2x/2=4/2

x=2

Then:

FJ=3x-1→FJ=3(2)-1→FJ=6-1→FJ=5

EJ=x+3→EJ=2+3→EJ=5

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Step-by-step explanation:

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