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zheka24 [161]
4 years ago
12

Which expressions would complete this equation so that it has infinitely many solutions?

Mathematics
2 answers:
inessss [21]4 years ago
5 0
8+2(8x-6)

=8+2(8x-6)

=8+16x-12

=16x-4

=4(4x-1)
natali 33 [55]4 years ago
4 0
8+2(8x-6)=8+2\times8x+2\times(-6)=8+16x-12\\\\=16x-4=4\times4x-4\times1=4(4x-1)\\\\Answer:\boxed{D.}

The\ equation\ has\ infinitely\ many\ solutions\ if\ left\ side\ of\ this\\equation\ is\ that\ same\ like\ right\ side.
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Which of the following is a factor of 2x4 + 22x3 + 60x2?
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2x^4 + 22x^3 + 60x^2 

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Which graph matches the inequality?
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Simon has more money than Kande. if Simon gave Kande K20, they would have the same amount. While if Kande gave Simon $22, Simon
motikmotik

Given parameters;

  Let us solve this problem step by step;

Let us represent Simon's money by S

Kande's money by K

  • Simon has more money than Kande

               S > K

  •  if Simon gave Kande K20, they would have the same amount;

 if Simon gives $20, his money will be  S - 20 lesser;

      When Kande receives $20, his money will increase to K + 20

                     S - 20  = K + 20   ------ (i)

  • While if Kande gave Simon $22, Simon would then have twice as much as Kande;

          if Kande gave Simon $22, his money will be K - 22

    Simon's money, S + 22;

                  S + 22  = 2(K - 22)    ------ (ii)

Now we have set up two equations, let us solve;

         S - 20  = K + 20  ---- i

         S + 22  = 2(K - 22)  ;       S + 22  = 2K - 44  ---- ii

So,      S - 20  = K + 20

          S + 22  = 2K - 44

subtract both equations;

               -20 - 22  = (k -2k)  + 64

                   -42  = -k + 64

                       k  = 106

Using equation i, let us find S;

            S - 20 = K + 20

             S - 20  = 106 + 20

              S = 106 + 20 + 20  = 146

Therefore, Kande has $106 and Simon has $146

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