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SVEN [57.7K]
2 years ago
6

At the beginning of spring McKenzie planted a small sunflower in her backyard when it first planted the sunflower was 10 inches

tall The sunflower then began to grow at a rate of 2.5 inches per week how tall what does sunflower be after two weeks how tall was the sunflower be after The sunflower then began to grow at a rate of 2.5 inches per week how tall what does sunflower be after two weeks how tall were the sunflower be after W weeks
Mathematics
1 answer:
katrin [286]2 years ago
6 0

Answer: 15 inches tall

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Answer:

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Step-by-step explanation:

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3 years ago
Hiow do you solve 3+3j=10+3j
vodomira [7]
No solution! Hope this helped
6 0
2 years ago
Factor the trinomial x^2 - 3x - 40
Elenna [48]
The answer is (x+5)(x-8)
Hope this helps
8 0
3 years ago
Read 2 more answers
If 0.9x-1.3=-3.1, what is the value of x-0.8?
Butoxors [25]
−<span>2.8
</span>Okay so "0.9x-1.3=-3.1" x=-2
 
<span><span><span>0.9x</span>−1.3</span>=<span>−3.1

</span></span>add 1.3 to both sides

<span><span><span><span>0.9x</span>−1.3</span>+1.3</span>=<span><span>−3.1</span>+1.3

</span></span><span><span>0.9x</span>=<span>−1.8

</span></span>divide both sides by 0.9

<span><span><span>0.9x/</span>0.9</span>=<span><span>−1.8/</span><span>0.9

</span></span></span>x=<span>−2</span>

So if you plug in -2 into "x-0.8" you get −2.8

<span>=<span><span>−2</span>−0.8

</span></span><span>=<span><span>−2-</span><span>0.8

</span></span></span><span>=<span>−2.8

</span></span>Hope this helps. 
3 0
3 years ago
Read 2 more answers
A right triangle is formed in the first quadrant by the x- and y-axes and a line through the point (5, 3), as shown in the figur
Whitepunk [10]

The area of the triangle as a function of x is A = 3x^2/[2(x -5)] and the domain is x > 5

<h3>Write the area A of the triangle as a function of x</h3>

From the figure, we have the following points:

(0,y), (5,3), and (x,0)

Next, we calculate the slopes between the points.

This is calculated as follows:

  • Slope between (0,y) and (5,3) = [y - 3]/[0 - 5] = [3 - y]/5
  • Slope between (5,3) and (x,0) = [3 - 0]/[5 - x] = 3/[5 - x]

The slopes are equal.

So, we have:

[3 - y]/5 = 3/[5 - x]

Cross multiply

(3 - y)(5 -x) = 15

Divide by 5 - x

(3 - y) = 15/(5 -x)

This gives

y = 3 - 15/(5 -x)

This gives

y = [15- 3x - 15]/[5 - x]

Evaluate

y = 3x/(x - 5)

The area is calculated as:

Area = 1/2 * xy

So, we have:

Area = 1/2 * x * 3x/(x - 5)

Evaluate

Area = 3x^2/[2(x -5)]

Hence, the area of the triangle as a function of x is A = 3x^2/[2(x -5)]

<h3>The domain of the function</h3>

We have:

A = 3x^2/[2(x -5)]

Set the denominator > 0

2(x - 5) > 0

Divide by 2

x - 5 > 0

Add 5 to the sides

x > 5

Hence, the domain is x > 5

Read more about domains at:

brainly.com/question/2428614

#SPJ1

6 0
2 years ago
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