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ch4aika [34]
3 years ago
15

NEED HELP!!! WILL GIVE BRAINLIEST FOR EXPLAINING ANSWERS.

Mathematics
1 answer:
amm18123 years ago
4 0
The data is left skewed.  The median is 5.  The mean is 5.15.  The mean would be more affected by adding a data point at 20.

Looking at the "tail" of the data, since it is longer at the left, the data is left skewed.

To find the median, you can write the data in order from least to greatest:
2, 3, 4, 4, 5, 5, 5, 6, 6, 6, 7, 7, 7

The middle value is 5.

To find the mean, find the sum of the data and divide by the number of data points (13):

2+3+4+4+5+5+5+6+6+6+7+7+7 = 67; 67/5 = 5.15.

Adding a data point of 20, the sum changes to 87; divide this by 14, and the mean changes to 6.2.  This is a change of 1.05.  The median, however, only shifts to 5.5, which is a change of 0.5.
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Sara says, "If you subtract 19 from my number and multiply the difference by - 6, the result is - 72." What is Sara's number?​
deff fn [24]
19-7 equals 12. 12 times -6=-72. Sara’s number is 7
4 0
3 years ago
Read 2 more answers
Evaluate the numerical expression. − 1 3 − (− 4 9 )
notka56 [123]
Two negatives make a positive so, -13 - (-49) equals -13 + 49, or 49-13, they are all the same thing, all equal to 36. 
6 0
3 years ago
The width of Estelle's rectangular living room is 4 meters, and the distance between opposite corners is 7 meters. What is the l
Crank

Answer:

5.7 meters

Step-by-step explanation:

Image a rectangle being cut diagonally in half, that would lead to two triangles. We can use the pythagorean theorem to find the missing side.

7 is the hypotenuse and 4 is the side length

4^2+x^2=7^2

16+x^2=49

sqrx=sqr(49-16)

x=sqr33

x=5.74

Rounded to the nearest tenth is 5.7

6 0
3 years ago
Just help please need to pass
Anni [7]

Answer: \frac{1}{10}

Step-by-step explanation:

First, we need to find the common denominator

The easiest way to do this is by multiplying the two given denominators, which are 2 and 5.

2 × 5 = 10

So, our common denominator is 10. Then, multiply the numerators of the two fractions by 2 and 5. Here's why:

\frac{3*2}{5*2} = \frac{6}{10}         We multiplied the top and bottom by 2 to make sure our new fraction stays equivalent to the original fraction.

Do the same thing for the other one:

\frac{1*5}{2*5} = \frac{5}{10}

Finally, subtract the two fractions to find the difference between the two times:

\frac{6}{10} -\frac{5}{10} = \frac{1}{10}

The reason we used the common denominator is because we can only add or subtract fractions if they have the same denominator.

7 0
3 years ago
Read 2 more answers
Show 2 different solutions to the task.
laila [671]

Answer with Step-by-step explanation:

1. We are given that an expression n^2+n

We have to prove that this expression is always is even for every integer.

There are two cases

1.n is odd integer

2.n is even integer

1.n is an odd positive integer

n square is also odd integer and n is odd .The sum of two odd integers is always even.

When is negative odd integer then n square is positive odd integer and n is negative odd integer.We know that difference of two odd integers is always even integer.Therefore, given expression is always even .

2.When n is even positive integer

Then n square is always positive even integer and n is positive integer .The sum of two even integers is always even.Hence, given expression is always even when n is even positive integer.

When n is negative even integer

n square is always positive even integer and n is even negative integer .The difference of two even integers is always even integer.

Hence, the given expression is always even for every integer.

2.By mathematical induction

Suppose n=1 then n= substituting in the given expression

1+1=2 =Even integer

Hence, it is true for n=1

Suppose it is true for n=k

then k^2+k is even integer

We shall prove that it is true for n=k+1

(k+1)^1+k+1

=k^1+2k+1+k+1

=k^2+k+2k+2

=Even +2(k+1)[/tex] because k^2+k is even

=Sum is even because sum even numbers is also even

Hence, the given expression is always even for every integer n.

3 0
3 years ago
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