Area of the polygon defined by the given points is 62.5 sq units
Step-by-step explanation:
Step 1 :
Let P be the point (-5,0) Q = (0,-5), R = (-15,-20) and S = (20,-15)
We have to to find the area of the polygon PQRS
Step 2 :
The area of polygon given the vertices (x
is given by
Area = mod ( 
) ÷ 2
Where 
is the vertex n's x coordinate , 
is the vertex n's y coordinate
Substituting the corresponding values ,
Area of PQRS = mod ( (25 - 0)+ (0-75) +(300-300) +( 0-75) ) ÷ 2
= mod (25-75+0-75) ÷ 2
= mod (-125) ÷ 2 = 125 ÷ 2 = 62.5 sq units
Step 3 :
Answer :
Area of the polygon defined by the given points is 62.5 sq units
Step-by-step explanation:
5 = 12 Cross multiply
2.35 x
5x = 28.2 Divide 5 on both sides to isolate the variable
x = 5.64
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Answer:
T = 4B + 10C
Step-by-step explanation:
Since there are 4 doughnuts in a bag then there are 4B doughnuts in B bags
Since there are 10 doughnuts in a carton then there are 10C doughnuts in C cartons, thus summing the two quantities gives
T = 4B + 10C
Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
The correct answer for this question is that there are 72 2-inch segment in 12ft. Hopefully that answered your question for you!
