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rosijanka [135]
3 years ago
12

Find the range of the function rule y=5x-2 for the domain (-1/2, 1/4th, and 2/5ths)

Mathematics
2 answers:
Vesna [10]3 years ago
4 0
Take the derivative of the equation 4 times. f 4 (x)=0.

Over [174]3 years ago
4 0

Answer:

{-1/2, 1/4, 2/5}

Step-by-step explanation:

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If you meet five classmates, what is the probability that three are female?
klasskru [66]

Answer:

3/5 is probability of female out of 5 classmates.

hope it helps

<h3>stay safe healthy and happy.</h3>
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3 years ago
HELP ME PLEASAAASE I WANNA PASS
Tpy6a [65]

Answer:

b

Step-by-step explanation:

7 0
3 years ago
a certain test is worth 135 points. how many points (rounded to the nearest point) are needed to obtain a score of 85%?
yanalaym [24]

To obtain a score of 85% on a test worth 135 points, one needs to get 115 points. By using proportions, we get the required value.

<h3>How to write proportions?</h3>

A proportion is defined as an equality between two ratios.

Consider two ratios a:b and c:d. Then, the proportion we can write,

a: b = c : d

Then, the simplification we have for this proportion is

a/b = c/d or ad = bc

<h3>Calculation:</h3>

It is given that, a certain test is worth 135 points.

One to get 85% on this test, he/she needs to get X number of points.

So, we can write the proportions as

X : 135 = 85 : 100

⇒ X/135 = 85/100

⇒ X = 85/100 × 135

∴ X = 114.75 ≅ 115 points

Learn more about proportions at the following link:

brainly.com/question/140018

#SPJ4

7 0
1 year ago
Two factories I and II produce phones for brand ABC. Factory I produces 60% of all ABC phones, and factory II produces 40%. 10%
denpristay [2]

Answer:

0.3721 or 37.21%

Step-by-step explanation:

P(I) = 0.60; P(II) = 0.40;

P(not defective I) = 0.90; P(not defective II) = 0.80

The probability that the phone came from factory II, given that is not defective, is determined by the probability of a phone from factory II not being defective divided by the probability of a phone not being defective.

P(II|not) = \frac{P(II)*P(not_{II})}{P(II)*P(not_{II})+P(I)*P(not_{I})}\\P(II|not) = \frac{0.40*0.80}{0.40*0.80+0.60*0.90}\\ P(II|not) =0.3721 = 37.21\%

The probability is 0.3721 or 37.21%.

4 0
3 years ago
Which of the following statements is true regarding the difference between a Descriptive investigation and an Experimental inves
Margarita [4]

Answer:

where are they

Step-by-step explanation:

wehre

3 0
3 years ago
Read 2 more answers
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