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Ivanshal [37]
3 years ago
11

20 students chose their lunch

Mathematics
2 answers:
Phantasy [73]3 years ago
3 0

Answer:

20 students chose their lunch

Step-by-step explanation:

Jet001 [13]3 years ago
3 0
20 students is the answer. That a weird question. Btw
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I’ve been confused on this problem for awhile :(
AlladinOne [14]

Answer:

<em><u>D</u></em><em><u> </u></em><em><u>7</u></em><em><u>,</u></em><em><u> </u></em><em><u>-</u></em><em><u>1</u></em><em><u>2</u></em> is the answer hope this helps✌

4 0
3 years ago
Read 2 more answers
X varíes directly with y and z. X =1200 when y =20 and z=30 find x when y=10 and z=20
Naya [18.7K]

Answer:

Value of x = 400

Step-by-step explanation:

Joint variation states that describes a situation where a variable depends on two (or more) other variables, and varies directly with some of them.

Given: x varies directly with y and  z.

i.e x \propto y and x \propto z

then we have the joint variation as;

x = k yz ......[1] where k is the constant variation.

Substitute the value of x =1200 when y =20 and z = 30 to solve for k;

1200 = k (20)(30)

Simplify:

1200 = 600k

Divide both sides by 600 we get;

k = 2

Now, substitute k =2 , y =10 and z = 20 to find x;

Using [1] we have;

x = 2 \times (10)(20) = 2 \times 200

Therefore, the value of x is, 400



7 0
3 years ago
Read 2 more answers
Convert 5.764764764 to a rational expression
NISA [10]

Answer: 5 and 764 over 999

5764 over 9999

5 and 764 over 99

5 and 999 over 764

Step-by-step explanation:

8 0
3 years ago
22. A liver cell is about 20 um in diameter. How many liver cells would it take to form an end to end chain 10 in long?
34kurt

The number of liver cells it would take to form an end to end chain 10 in long is 12,700 liver cells

<h3>Calculating quantity</h3>

From the question, we are to determine how many liver cells it would take to form an end to end chain 10 in long

First, we will convert 10 in to meters

1 inch = 0.0254

∴ 10 inches = 0.254 m

From the giving information,

A liver cell is about 20 μm in diameter

∴ The number of liver cells it would take to form an end to end chain 10 in long = 0.254 m / 20 μm

= 0.254 m / (20 ×10⁻⁶) m (NOTE: 1μm = 10⁻⁶m)

= 12700

Hence, the number of liver cells it would take to form an end to end chain 10 in long is 12,700 liver cells

Learn more on Calculating quantity here: brainly.com/question/2021001

#SPJ1

8 0
2 years ago
The actual size is 200 meters what is the size of the model in cm ?
harkovskaia [24]
20,000 cm!!!!!!!!!
hope i helped!!!!!!!

8 0
3 years ago
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