Given:-
To graph and explain.
So the graph of the given function is,
An integral in mathematics is either a numerical value equal to the area under the graph of a function for some interval or a new function, the derivative of which is the original function.
Answer:
The error is at step (3) .
The correct step (3) will be,
= 
[by using the laws of indices]
All other steps are correct.
Step-by-step explanation:
The error is at the step (3) , because the student has tried to prove the quotient rule of logarithms by using the property i.e., 'The quotient rule of logarithm' itself , i.e. ,by assuming the property does hold before proving it. So, the proof is fallacious.
The correct step (3) will be,
= [by using the laws of indices]
All other steps are correct.
Answer:
a linear equation in x and y
Step-by-step explanation:
The given equation is a linear equation (all variables to the first power) relating the variables x and y. There are an infinite number of values of x and y that will satisfy this equation.
When graphed on an x-y plane, those solution values will fall on a straight line with a slope of 2. It will cross the y-axis at y=32, and the x-axis at x=-16.
The correct question is
<span>Given cos theta=4/9 and csc theta < 0 find sin theta and tan theta
</span>
we know that
csc theta=1/sin theta
if csc theta < 0
then
sin theta < 0
we have that
<span>cos theta=4/9
we know that
sin</span>² theta+cos² theta=1
so
sin² theta=1-cos² theta-----> 1-(4/9)²----> 1-(16/81)----> 65/81
sin theta=-√(65/81)---->-√65/9
the answer Part a) is
sin theta=-√65/9
Part b) find tan theta
tan theta=sin theta/cos theta
tan theta=(-√65/9)/(4/9)-----> tan theta=-√65/4
the answer part b) is
tan theta=-√65/4
Answer: y = 3x/4 + 22
Step-by-step explanation:
The equation of line l is -3y + 4x = 9
-3y + 4x = 9
3y = 4x -9
y = (4x -9)/3= 4x/3 - 3
From the slope-intercept equation,
y = mx +c
Where m= slope
Comparing both equations, we have
m = 4/3
If the new line that parallel to line l, that means they have the same slope
So, slope if new line is 3/4.
Points =(-12, 6)
From y = mx + c
x = -12,y = 6
6= 4/3 × -12 + c
6 = -16 + c
c = 6 + 16 = 22
Therefore
The equation of the line that is parallel to line l and passes through the point (-12,6) ,
y = 3x/4 + 22
