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3 years ago

One a piece of paper graph this system of inequalities y<-1/3x+3, y>3x+2

Mathematics

1 answer:

kolbaska11 [484]3 years ago

8 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$y < -\frac{1}{3}x+3$ ----> inequality A

The solution of the inequality A is the shaded area below the dashed line $y=-\frac{1}{3}x+3$

The slope of the dashed line is negative

The y-intercept of the dashed line is 3

The x-intercept of the dashed line is 9

$y > 3x+2$ ----> inequality B

The solution of the inequality B is the shaded area above the dashed line $y=3x+2$

The slope of the dashed line is positive

The y-intercept of the dashed line is 2

The x-intercept of the dashed line is -2/3

The solution of the system of inequalities is the shaded area between the two dashed lines

see the attached figure

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Geometry help greatly needed, check photo for more information! <3

vlabodo [156]

Answer:

$\huge\boxed{\sf x = 55\°}$

Step-by-step explanation:

When a quadrilateral is inscribed in a circle, the opposite angles of it add up to 180 degrees.

Here,

∠DCB + ∠DAB = 180 (Opposite angles of a quad inscribed in a circle.)

<u>Given that:</u> ∠DCB = 135° and ∠DAB = x

135 + x = 180

Subtract 135 to both sides

x = 180 - 135

x = 55°

$\rule[225]{225}{2}$

Hope this helped!

8 0

2 years ago

rectangle ABCD is graphed in the cordinate plane. The following are the verticies of the rectangle; A(-6,-4),B(-4,-4),C(-4,-2),

Sholpan [36]

Answer:

Therefore Perimeter of Rectangle ABCD is 4 units

Step-by-step explanation:

Given:

ABCD is a Rectangle.

A(-6,-4),

B(-4,-4),

C(-4,-2), and

D (-6,-2).

To Find :

Perimeter of Rectangle = ?

Solution:

Perimeter of Rectangle is given as

$\textrm{Perimeter of Rectangle}=2(Length+Width)$

Length = AB

Width = BC

Now By Distance Formula we have'

$l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting the values we get

$l(AB) = \sqrt{((-4-(-6))^{2}+(-4-(-4))^{2} )}$

$l(AB) = \sqrt{((2)^{2}+(0)^{2} )}=2\ unit$

Similarly

$l(BC) = \sqrt{((-4-(-4))^{2}+(-2-(-4))^{2} )}$

$l(BC) = \sqrt{((0)^{2}+(2)^{2} )}=2\ unit$

Therefore now

Length = AB = 2 unit

Width = BC = 2 unit

Substituting the values in Perimeter we get

$\textrm{Perimeter of Rectangle}=2(2+2)=2(4)=8\ unit$

Therefore Perimeter of Rectangle ABCD is 4 units

8 0

2 years ago

One day at St. Philip's High School, 1/2 of the pupils walked to school, 1/5 of the pupils came to school by bus, and the remai

Doss [256]

Let P be the number of kids,
we know P>57
take 1-(1/2)-(1/5)=3/10
therefore 57 is 3/10P
3/7P=57
P=57*7/3=133 is the answer
it would be incorrect if we didnt get a positive integer.

7 0

3 years ago

Hiya! I need help please! Thanks I really appreciate it!<br><br> (2 screenshots included)

Sidana [21]

Answer should be Vertical

3 0

2 years ago

Read 2 more answers

After you subtract both sides by 4. How can you solve for 3x in this equation?

Nataly [62]

Answer:

Step-by-step explanation:

Once you subtract both sides, the 4 is gone then the 10 is subtracted into a 6. You go to the 3x, and just like what you did to the 4 you do the opposite and divide the 3 by itself and the 6 by 3 as well.

8 0

3 years ago